[英]How to parse this XML in Android?
I am quite new to XML parsing and I have my method of parsing XML. 我对XML解析非常陌生,并且有解析XML的方法。 Only that method is for simple XML layouts with just 1 child node. 只有该方法适用于只有1个子节点的简单XML布局。
I now have to parse an XML file with childs that have childs that have childs (got it :)?) 我现在必须解析一个XML文件,该XML文件中的childs包含childs(get :)?
This is the parse-method I have now: 这是我现在拥有的解析方法:
protected Map<String, Maatschappij> getAutopechTel() {
Map<String, Maatschappij> telVoorAutopech = new HashMap<String, Maatschappij>();
try {
DocumentBuilder builder = DocumentBuilderFactory.newInstance()
.newDocumentBuilder();
Document doc = builder.parse(getAssets().open("autopech.xml"));
NodeList nl = doc.getElementsByTagName("dienst");
for (int i = 0; i < nl.getLength(); i++) {
Node node = nl.item(i);
Maatschappij maat = new Maatschappij();
maat.setNaam(Xml.innerHtml(Xml.getChildByTagName(node, "naam")));
maat.setTel(Xml.innerHtml(Xml.getChildByTagName(node, "tel")));
telVoorAutopech.put(maat.getTel(), maat);
}
} catch (Exception e) {
}
return telVoorAutopech;
}
How must I adjust this in order to parse this type of XML file: 为了解析这种类型的XML文件,我必须如何调整它:
<Message>
<Service>Serviceeee</Service>
<Owner>Bla</Owner>
<LocationFeedTo>Too</LocationFeedTo>
<Location>http://maps.google.com/?q=52.390001,4.890145</Location>
<Child1>
<Child1_1>
<Child1_1_1>ANWB</Child1_1_1>
</Child1_1>
</Child1>
<Message>
You can use SAXParser
to parse XML in Android : 您可以使用SAXParser
在Android中解析XML:
Here is a detailed tutorial with example and also another one here by IBM developerWorks . 这是带示例的详细教程, IBM developerWorks的另一个 示例 。
DOM Parser is slow and consume a lot memory if it load a XML document which contains a lot of data. 如果DOM Parser加载包含大量数据的XML文档,则速度很慢并且会占用大量内存。 Please consider SAX parser as solution for it, SAX is faster than DOM and use less memory. 请考虑使用SAX解析器作为解决方案,SAX比DOM更快,并且使用更少的内存。
Try this one out but I haven't tested this code yet. 试试这个,但是我还没有测试这段代码。 It recursively traverses all the nodes and adds which are ELEMENT_NODE
to the Vector<Node>
. 它递归地遍历所有节点,并将ELEMENT_NODE
添加到Vector<Node>
。
public void traverseNodes(Node node, Vector<Node> nodeList)
{
if(node.getNodeType() == Node.ELEMENT_NODE)
{
nodeList.add(node);
if(node.getChildNodes().getLength() >= 1)
{
NodeList childNodeList = node.getChildNodes();
for(int nodeIndex = 1;nodeIndex < childNodeList.getLength(); nodeIndex++)
{
traverseNodes(childNodeList.item(nodeIndex),nodeList);
}
}
}
}
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