读取一个2048字节的文件

Question

Guys i have a file which has only one line. The file has no encoding it is a simple text file with single line.

For every 2048 byte in a line , there is new record of 151 byte (totally 13*151 byte = 1945 records + 85 byte empty space) . similarly for the next 2048 bytes.

What is the best file i/o to use? i am thinking of reading 2048 bytes from file and storing it in an array .

while (offset < fileLength &&(numRead=in.read(recordChunks, offset,alength)) >= 0) 
{ 
}

how can i get from the read statement only 2048 bytes at a time . i am getting IndexOutofBoundException.

Answer 1

只需使用FileInputStream ，各种read方法将允许您执行所需的操作。

Answer 2

How about:

byte byte1 = dataArray[0];
byte byte2 = dataArray[1];

Answer 3

In my opinion, the easiest way to read data from a file is to use a BufferedReader :

try
{
    BufferedReader br = new BufferedReader(new FileReader("your_file"));

    //Read the first line
    String s = br.readLine();
}
catch(Exception e)
{
    e.printStackTrace();
}

Then just do what you want with the String you get !

Hope this helps.