[英]XslCompiledTransform eats my DOCTYPE
Made a xslt template with output instruction for <DOCTYPE>
: 制作了一个带有<DOCTYPE>
输出指令的xslt模板:
<xsl:output media-type="text/html" method="html" encoding="windows-1251" doctype-public="-//W3C//DTD XHTML 1.1//EN" doctype-system="http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd" omit-xml-declaration="yes"/>
In xsl-debug I'm receiving right 在xsl-debug中,我收到了正确的权利
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1//EN" "http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd">
on top of the html. 在HTML之上。
But when I'm using XslCompiledTransform etc.. output starts from 但是当我使用XslCompiledTransform等时,输出开始了
<html xmlns="http://www.w3.org/1999/xhtml">
So, DOCTYPE is missed. 所以,错过了DOCTYPE。 Why? 为什么? Right properties of XslCompiledTransform
initialized just like I set in <xsl:output>
. 正如我在<xsl:output>
设置的那样初始化XslCompiledTransform
正确属性。
Code: 码:
using (var sw = new StringWriter())
{
XslCompiledTransform xslt = new XslCompiledTransform();
XmlEmbeddedResourceResolver resolver = new XmlEmbeddedResourceResolver();
xslt.Load("clires://DLLPATH/xsl/blank.xsl", XsltSettings.TrustedXslt, resolver);
XmlWriterSettings set = new XmlWriterSettings();
set.ConformanceLevel = ConformanceLevel.Auto;
xslt.Transform(ticket, XmlWriter.Create(sw, set));
return sw.ToString();
}
How can I get DOCTYPE from XslCompiledTransform? 如何从XslCompiledTransform获取DOCTYPE?
您需要使用XslCompiledTransform
OutputSettings属性中的XmlWriterSettings
XmlWriterSettings set = xslt.OutputSettings;
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