[英]Except Python codec errors?
File "/usr/lib/python3.1/codecs.py", line 300, in decode
(result, consumed) = self._buffer_decode(data, self.errors, final)
UnicodeDecodeError: 'utf8' codec can't decode byte 0x92 in position 805: invalid start byte
Hi, I get this exception. 嗨,我得到了这个例外。 How do I catch it, and continue reading my files when I get this exception.
如何捕获它,并在我收到此异常时继续读取我的文件。
My program has a loop that reads a text file line-by-line and tries to do some processing. 我的程序有一个循环,逐行读取文本文件并尝试进行一些处理。 However, some files I encounter may not be text files, or have lines that are not properly formatted (foreign language etc).
但是,我遇到的某些文件可能不是文本文件,或者行格式不正确(外语等)。 I want to ignore those lines.
我想忽略这些界限。
The following is not working 以下不起作用
for line in sys.stdin:
if line != "":
try:
matched = re.match(searchstuff, line, re.IGNORECASE)
print (matched)
except UnicodeDecodeError, UnicodeEncodeError:
continue
Look at http://docs.python.org/py3k/library/codecs.html . 请查看http://docs.python.org/py3k/library/codecs.html 。 When you open the codecs stream, you probably want to use the additional argument
errors='ignore'
当您打开编解码器流时,您可能希望使用其他参数
errors='ignore'
In Python 3, sys.stdin
is by default opened as a text stream (see http://docs.python.org/py3k/library/sys.html ), and has strict error checking. 在Python 3中,默认情况下
sys.stdin
作为文本流打开(请参阅http://docs.python.org/py3k/library/sys.html ),并且具有严格的错误检查。
You need to reopen it as an error-tolerant utf-8 stream. 您需要将其重新打开为容错的utf-8流。 Something like this will work:
这样的东西会起作用:
sys.stdin = codecs.getreader('utf8')(sys.stdin.detach(), errors='ignore')
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