如何添加显示“ $ user_id已删除”或“找不到$ user_id”的消息？

Question

How would I add a message that says "$user_id Deleted" or "$user_id not found?"

  <?php

  $con=mysql_connect("localhost","root","");

  if(!$con) {
      die('could not connect:'.mysql_error());
  }

  mysql_select_db("final?orgdocs", $con);

  $user_id = $_POST["user_id"];

  $result = mysql_query("delete from account where user_id='$user_id' ");


  ?>

Answer 1

$user_id = $_POST["user_id"];

if(isset($user_id)) {
    $result = mysql_query("delete from account where user_id='$user_id' ");

    $affected_rows = mysql_affected_rows();    // how many rows deleted?

} else {
    $user_id = "";
    $result = false;
    $affected_rows = 0;
}

if($result == true && $affected_rows > 0) {
    echo "User " . $user_id . " deleted."; 
} else {
    echo "User " . $user_id . " not found.";
}

This should help get you started. You can return the response to your calling page and then use a JavaScript library like JQuery to display it in your HTML.

EDIT: I edited the code to get the affected rows as it's possible for a delete query to return true but delete 0 records.

http://www.php.net/manual/en/function.mysql-affected-rows.php

Answer 2

<?php

$con = mysql_connect("localhost", "root", "");

if (!$con) {
    die('could not connect:'  .mysql_error());
}

mysql_select_db("final?orgdocs", $con);

$user_id = (int)$_POST["user_id"];

$result = mysql_query("delete from account where user_id=$user_id");

$affected_rows = mysql_affected_rows();

if ($affected_rows) {
    echo "User ID '$user_id' deleted";
} else {
    echo "User ID '$user_id' not found";
}

?>

Answer 3

echo $ user_id +'已删除或未找到';

Answer 4

只需将其添加到最后：

return "user id " . ( $deleted ? "deleted" : "not found");

Answer 5

From the mysql_query man page:

For SELECT, SHOW, DESCRIBE, EXPLAIN and other statements returning resultset, mysql_query() returns a resource on success, or FALSE on error.

For other type of SQL statements, INSERT, UPDATE, DELETE, DROP, etc, mysql_query() returns TRUE on success or FALSE on error.

So, it should continue to something like this:

if ($result === TRUE) {
    echo "Account deleted.";
} else if ($result === FALSE) {
    echo "Account not found.";
}