[英]Spring: Inject URL for classpath resource
I want to inject the URL of a classpath resource in a way that does not create a dependency on Spring in the Bean. 我想以一种不在Bean中创建对Spring的依赖的方式注入类路径资源的URL。 Meaning, the bean should not use Spring's interfaces/classes.
意思是,bean不应该使用Spring的接口/类。 How can I do that?
我怎样才能做到这一点?
Spring is able to convert classpath:...
values into java.net.URL
implicitly: Spring能够隐式地将
classpath:...
值转换为java.net.URL
:
public class Foo {
private URL url;
...
}
. 。
<bean class = "Foo">
<property name = "url" value = "classpath:..." />
</bean>
从axtavt的回答开始,如果你允许自己在bean中使用Spring注释,你可以这样做:
@Value("classpath:myClasspathLocation") private URL url;
create your own implementation of a spring resource by extending the org.springframework.core.io.ClassPathResource like MyClasspathResource extends ClassPathResource and inject this type into your bean. 通过扩展org.springframework.core.io.ClassPathResource来创建自己的spring资源实现,如MyClasspathResource扩展ClassPathResource并将此类型注入到bean中。 Like this you do not have any dependency to spring and can later reimplement your resource with something else.
像这样,你对spring没有任何依赖,以后可以用其他东西重新实现你的资源。
<bean class="myBean">
<property name="classPathType">
<bean class="org.test.bla.MyClasspathResource">
<constructor-arg index="0" value="classpath:/org/test/bla/MyUrl" />
</bean>
</property>
</bean>
There is hardly anything non-spring that's equivalent to Spring's resource concept . 几乎没有任何非弹簧相当于Spring的资源概念 。
You could for example use Guava 's InputSupplier as an alternative, but you are missing powerful standard spring features if you do. 例如,您可以使用Guava的InputSupplier作为替代方案,但如果您这样做,则缺少强大的标准弹簧功能。
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