在循环中连接 PyQt4 中的插槽和信号

Question

Im trying to build a calculator with PyQt4 and connecting the 'clicked()' signals from the buttons doesn't work as expected. Im creating my buttons for the numbers inside a for loop where i try to connect them afterwards.

def __init__(self):
    for i in range(0,10):
        self._numberButtons += [QPushButton(str(i), self)]
        self.connect(self._numberButtons[i], SIGNAL('clicked()'), lambda : self._number(i))

def _number(self, x):
    print(x)

When I click on the buttons all of them print out '9'. Why is that so and how can i fix this?

Answer 1

This is just, how scoping, name lookup and closures are defined in Python.

Python only introduces new bindings in namespace through assignment and through parameter lists of functions. i is therefore not actually defined in the namespace of the lambda , but in the namespace of __init__() . The name lookup for i in the lambda consequently ends up in the namespace of __init__() , where i is eventually bound to 9 . This is called "closure".

You can work around these admittedly not really intuitive (but well-defined) semantics by passing i as a keyword argument with default value. As said, names in parameter lists introduce new bindings in the local namespace, so i inside the lambda then becomes independent from i in .__init__() :

self._numberButtons[i].clicked.connect(lambda checked, i=i: self._number(i))

^{UPDATE: clicked has a default checked argument that would override the value of i , so it must be added to the argument list before the keyword value.}

A more readable, less magic alternative is functools.partial :

self._numberButtons[i].clicked.connect(partial(self._number, i))

I'm using new-style signal and slot syntax here simply for convenience, old style syntax works just the same.

Answer 2

You are creating closures. Closures really capture a variable, not the value of a variable. At the end of __init__ , i is the last element of range(0, 10) , ie 9 . All the lambdas you created in this scope refer to this i and only when they are invoked, they get the value of i at the time they are at invoked (however, seperate invocations of __init__ create lambdas referring to seperate variables.)

There are two popular ways to avoid this:

1. Using a default parameter: lambda i=i: self._number(i) . This work because default parameters bind a value at function definition time.
2. Defining a helper function helper = lambda i: (lambda: self._number(i)) and use helper(i) in the loop. This works because the "outer" i is evaluated at the time i is bound, and - as mentioned before - the next closure created in the next invokation of helper will refer to a different variable.

Answer 3

Use the Qt way, use QSignalMapper instead.