如何创建自定义 python 解释器？ 即某些模块已经包括在内？

Question

If you've used Ruby on Rails, I'm thinking of the feature where the user types

'rails console'

and instantly gets a Ruby console with rails and the current app already loaded.
I want to make something like this for a python program I'm working on, does anyone know how I would get to type say,

'python myPythonConsole.py'

and open up a regular python interpreter but with my program and all its dependencies loaded?

Answer 1

If I understand you correctly then you might want python -i myPythonConsole.py . It gives you a console when the script has finished so you have to run your application in a different thread.

To create a console in a script you would use the code module .

Answer 2

If you are using IPython (if you are not you should, it is an awesome python shell with TAB completion and many shortcuts) it is possible to set up profiles , which basically are named configurations.

Each configuration can import modules (and do other stuff) at startup.

Answer 3

Django does this with its "shell" command:

./manage.py shell

will open a Python shell with your Django settings loaded so you can import your project code interactively.

Source: http://code.djangoproject.com/browser/django/trunk/django/core/management/commands/shell.py

Answer 4

The real answer here is to use the PYTHONSTARTUP environment variable. See the tutorial section The interactive startup file .

Do your custom imports in a file interpreter.py , and configure

PYTHONSTARTUP=/path/to/interpreter.py

Next time your start Python, the custom code will be executed before you're dropped in the REPL shell.

Here's my customization:

import os
import sys
from pathlib import Path
from pprint import pprint
pp = pprint
P = Path

version = ".".join(str(number) for number in sys.version_info[0:3])
print(f"\nCustomized Python interpreter v{version} running from {sys.prefix}")