Python：从文本数据中删除html
[英]Python: strip html from text data
问题描述
My question is slightly related to: Strip HTML from strings in Python 
我的问题与以下内容有些相关： 从Python中的字符串中删除HTML
I am looking for a simple way to strip HTML code from text. 我正在寻找一种从文本中删除HTML代码的简单方法。 For example: 例如：
string = 'foo <SOME_VALID_HTML_TAG> something </SOME_VALID_HTML_TAG> bar'
stripIt(string)
Would then yield foo bar . 然后会产生foo bar 。
Is there any simple tool to achieve this in Python? 有什么简单的工具可以在Python中实现这一点吗？ The HTML code could be nested. HTML代码可以嵌套。
6 个解决方案
解决方案1
6 2011-01-06 00:47:24
import lxml.html
import re
def stripIt(s):
doc = lxml.html.fromstring(s) # parse html string
txt = doc.xpath('text()') # ['foo ', ' bar']
txt = ' '.join(txt) # 'foo bar'
return re.sub('\s+', ' ', txt) # 'foo bar'
s = 'foo <SOME_VALID_HTML_TAG> something </SOME_VALID_HTML_TAG> bar'
stripIt(s)
returns 回报
foo bar
解决方案2
5 已采纳 2011-01-05 19:45:51
from BeautifulSoup import BeautifulSoup
def removeTags(html, *tags):
soup = BeautifulSoup(html)
for tag in tags:
for tag in soup.findAll(tag):
tag.replaceWith("")
return soup
testhtml = '''
<html>
<head>
<title>Page title</title>
</head>
<body>text here<p id="firstpara" align="center">This is paragraph <b>one</b>.</p>
<p id="secondpara" align="blah">This is paragraph <b>two</b>.</p>
</body>
</html>'''
print removeTags(testhtml, 'b', 'p')
解决方案3
3 2013-05-24 03:04:53
You could use regex: 你可以使用正则表达式：
def stripIt(s):
txt = re.sub('<[^<]+?>.*?</[^<]+?>', '', s) # Remove html tags
return re.sub('\s+', ' ', txt) # Normalize whitespace
However, I would prefer Hugh Bothwell's solution as it would be more robust than pure regex. 但是，我更喜欢Hugh Bothwell的解决方案，因为它比纯正则表达式更强大。
解决方案4
2 2013-02-21 10:50:37
如果有人striptags此问题并且已经使用jinja模板语言：您可以在模板中使用过滤器striptags ，并在代码中使用函数jinja2.filters.do_striptags() 。
解决方案5
2 2011-01-05 19:34:22
Try this solution: 尝试此解决方案：
from BeautifulSoup import BeautifulSoup
def stripIt(string, tag):
soup = BeautifulSoup(string)
rmtags = soup.findAll(tag)
for t in rmtags:
string = string.replace(str(t), '')
return string
string = 'foo <p> something </p> bar'
print stripIt(string, 'p')
>>> foo bar
string = 'foo <a>bar</a> baz <a>quux</a>'
print stripIt(string, 'a')
>>> foo baz
Edit: This only works on validly nested tags, so for example: 编辑：这仅适用于有效嵌套标记，例如：
string = 'blaz <div>baz <div>quux</div></div>'
print stripIt(string, 'div')
>>> blaz
string = 'blaz <a>baz <a>quux</a></a>'
print stripIt(string, 'a')
>>> blaz <a>baz </a>
解决方案6
0 2011-01-05 19:47:49
You can take advantage of HTMLParser by overriding methods accordingly: 您可以通过相应地覆盖方法来利用HTMLParser：
from HTMLParser import HTMLParser
class HTMLStripper(HTMLParser):
text_parts = []
depth = 0
def handle_data(self, data):
if self.depth == 0:
self.text_parts.append(data.strip())
def handle_charref(self, ref):
data = unichr(int(ref))
self.handle_data(data)
def handle_starttag(self, tag, attrs):
self.depth += 1
def handle_endtag(self, tag):
if self.depth > 0:
self.depth -= 1
def handle_entityref(self, ref):
try:
data = unichr(name2codepoint[ref])
self.handle_data(data)
except KeyError:
pass
def get_stripped_text(self):
return ' '.join(self.text_parts)
def strip_html_from_text(html):
parser = HTMLStripper()
parser.feed(html)
return parser.get_stripped_text()
def main():
import sys
html = sys.stdin.read()
text = strip_html_from_text(html)
print text
if __name__ == '__main__':
main()
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