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更新数据库后如何刷新页面?

[英]How can I refresh a page when a database is updated?

How can I detect the latest updates made to a database and silently refresh a page when a change occurs? 发生更改时,如何检测对数据库的最新更新并以静默方式刷新页面?

Let's say the database access looks like: 假设数据库访问如下所示:

$host = "localhost";
$username = "root";
$password = "root";
$db = mysql_connect($host,$username,$password) or die(mysql_error());
mysql_select_db('ccr') or die(mysql_error());

Any ideas and samples would be appreciated. 任何想法和样品将不胜感激。 Thank you. 谢谢。

This is how I recently implemented a solution using jQuery. 这就是我最近使用jQuery实现解决方案的方式。

PHP increments a field in the database every time a significant update occurs. 每当发生重大更新时,PHP都会在数据库中增加一个字段。

<?php

//  Call this function when data changes
function update_clients()
{
    mysql_query( "UPDATE pageGen SET id = id + 1 LIMIT 1" );
}

//  Call this function to get the ID to pass to JavaScript
function get_update()
{
    $result = mysql_query( "SELECT id FROM pageGen LIMIT 1" );
    $update = mysql_result( $result, 0, 'id' );
    return $update;
}

?>

When the page is initially loaded, populate a JavaScript variable with a number from the database: 最初加载页面时,使用数据库中的数字填充JavaScript变量:

<script type="text/javascript">
var pageGenID = 25218603  //  generated by PHP
var processUpdate = function( response ) 
{
    if ( pageGenID < response ) 
    {
        replace_current_data_with_new_via_ajax();
        pageGenID = response;
    }
}
//  Compare our Page Generate ID against that of the server
var checkUpdates = function()
{
    serverPoll = setInterval( function()
    {
        $.get('script_to_return_latest_pageGenID.php', 
          { lastupdate: 1 }, 
          processUpdate, 'html');
    }, 10000 )
};

//  Check for updates every 10 seconds
$( document ).ready( checkUpdates );

</script>

Here is what I did and used the answer you marked but I think there is a few things to change there. 这是我做过的事情,并使用了您标记的答案,但我认为有一些事情需要更改。 In the main page ( that you want to refresh if something changed in the database). 在主页中(如果数据库中发生某些更改,您要刷新的页面)。 I created a table in my database called setting, in this table i created a row that called rowCounter. 我在数据库中创建了一个名为setting的表,在该表中创建了一个名为rowCounter的行。 the rowCounter is being updated when the numbers of rows in the table you check has been changed. 当您检查的表中的行数已更改时,将更新rowCounter。 so my code split in two blocks. 所以我的代码分为两个块。 one that giving me the number from the setting > rowCounter and the second is the script that give me the current number in the table. 第一个是从设置> rowCounter中给我数字,第二个是给我表中当前数字的脚本。 if they are not equal then I refresh the page. 如果它们不相等,则刷新页面。

so this is the first file you need 这是您需要的第一个文件
script_to_return_latest_pageGenID.php script_to_return_latest_pageGenID.php

// here you will make you connection query.

$result = mysql_query( "SELECT rowCounter FROM setting WHERE `id`='2'" );
$update = mysql_fetch_assoc($result);
        echo implode($update);

    $count=mysql_query("SELECT `id` FROM log_".$datestamp."")or die(mysql_error);
    $number =  mysql_num_rows($count);
//echo $number;

    $countFromSetting=mysql_query("SELECT `rowCounter` FROM setting  WHERE id='2'")or die(mysql_error);
    $numberFromSetting=implode(mysql_fetch_assoc($countFromSetting));

    if($number != $numberFromSetting)
        {
            mysql_query("UPDATE setting SET `rowCounter`='$number' WHERE `id`='2'")or die(mysql_error);

        }


In the main page you will write the two blocks of code I provided and you should put it before the script. 在主页中,您将编写我提供的两个代码块,并且应将其放在脚本之前。

$countFromSetting=mysql_query("SELECT `rowCounter` FROM setting  WHERE id='2'")or die(mysql_error);  
         $numberFromSetting=implode(mysql_fetch_assoc($countFromSetting));

After this code you put the script that will query every few seconds the php script, check if the numbers are not equal it will refresh the page. 在此代码之后,您放置了将每隔几秒钟查询一次php脚本的脚本,检查数字是否相等,它将刷新页面。

var pageGenID = "<?php echo $numberFromSetting; ?>"; 
var processUpdate = function( response ) {


var x=response;
//console.log(pageGenID); by removing the remarks you will see the compared numbers all the time.
//console.log(x);
if ( pageGenID != x ) 
{
    //replace_current_data_with_new_via_ajax();
    pageGenID = response;

    window.location.reload();       
   }
}

 var checkUpdates = function()
{
    serverPoll = setInterval( function()
  {

$.get('script_to_return_latest_pageGenID.php', 
      { lastupdate: 1 }, 
      processUpdate, 'html');
  }, 5000 ) };
    $( document ).ready( checkUpdates );

It would seem like you could use something like this, using a while loop. 似乎可以使用while循环来使用类似的方法。 This won't work for massive amounts of users (will probably crash PHP or SQL), and at some point you will have to reset the count variables in your script.: 这不适用于大量用户(可能会使PHP或SQL崩溃),并且在某些时候,您将不得不重置脚本中的count变量。

 <?PHP
 //initialize the variables somewhere before any of the following. do not use these
 //variables for any other purpose other than the refresh routines:
 $a==0;
 $b==0;
 //First design code within a function to refresh the database a single iteration. 
 fuction refresh(){
     insert code here to output database;
      }

 //Now, call function refresh in a loop at the spot in the code 
 //where we want to refresh the database. where $b here is equal to 
 //the number of times you want the database to automatically refresh 
 //before having to reset the variables to 0. 

 $b==1 
 while ($b!==$a){
      refresh();
      $a==$a+1;
      } 

 ?>

I believe you'd have to poll the database when you use PHP, PHP doesn't exist in a long running process as in the case of a Java container where the Java web application could create a persistent connection (in theory) you'll likely need to employ some sort of polling mechanism by which I mean setup a timer in Javascript or whatever your client code is to periodically make the request, in terms of increasing efficiency for this if need be you could create a flag on the users table and set the flag to indicate that the database has been invalidated since the user last polled, then your first check would be if invalidation has happened since that user last updated rather than sending everything to everyone all the time. 我相信您在使用PHP时必须轮询数据库,而在长时间运行的过程中就不存在PHP了,就像Java容器那样,Java Web应用程序可以创建持久连接(理论上),您会可能需要采用某种轮询机制,我的意思是在Javascript中设置一个计时器或使用您的客户端代码来定期发出请求,以提高效率(如果需要),您可以在users表上创建一个标志,设置标志以指示自从上次轮询用户以来数据库已失效,那么您的第一个检查将是自该用户上次更新以来是否发生了失效,而不是一直将所有内容发送给所有人。 Alternatively I think you'd need to abandon PHP for this task. 另外,我认为您需要放弃PHP才能完成此任务。

Ideea: 想法:

When you render a page with php , you can pass a js variable witch has keeps a "current database revision" ( a number ) . 使用php渲染页面时,可以传递js变量,而该变量保留了“当前数据库修订”(一个数字)。 On the page you make an ajax call once every 30 seconds a witch recives a new current database revision so to speak . 在页面上,您每30秒进行一次ajax调用,巫婆可以调用新的当前数据库修订版。 You test for those 2 and if the one you got from the ajax call is higher then it means you need to reload the page . 您需要测试这2个,如果从ajax调用中获得的那个更高,则意味着您需要重新加载页面。

On the server side you need a table to store the current revision , everytime you make a query from php you set the current revision +1 ( in the revision database table ) . 在服务器端,您需要一个表来存储当前修订,每次从php进行查询时,您都将当前修订设置为+1(在修订数据库表中)。 When you receive an ajax call from a client you read that number from the database and you pass it on to the cilent . 当您从客户端收到ajax调用时,您将从数据库中读取该号码,并将其传递给cilent。 You can setup a cronjob that will reset the counter every day . 您可以设置一个cronjob,它将每天重置计数器。

Strictly speaking, this is not possible. 严格来说,这是不可能的。 MySQL does not fire triggers back to PHP if something is changed. 如果发生更改,MySQL不会将触发器触发回PHP。 It's just not possible. 只是不可能。 Also, MySQL operates using sessions, so even if it could report a change in the database, you'd have to use a persistent connection in order for you to be able to access that sort of trigger. 另外,MySQL使用会话进行操作,因此,即使它可以报告数据库中的更改,您也必须使用持久连接才能访问这种触发器。

Now, if you want to execute select statements to detect a change in the database, that's different. 现在,如果要执行select语句以检测数据库中的更改,则有所不同。 Depending on how "new" you want your code to be (depending on how compatible you'd like it to be) you can use any one of the following to "poll" a PHP page to check for changes: Comet, AJAX, a forever frame, or HTML5's new WebSocket class. 根据您希望代码的“新”程度(取决于您希望的兼容性),可以使用以下任意一种方式“轮询” PHP页面以检查更改:Comet,AJAX,永久框架,或HTML5的新WebSocket类。

While other say use the client to detect a change through variables like a database version stored in javascript, I'd advise that you leave that server sided simply because people who know how to inject javascript will be able to change that value, which may produce undesired or even malicious results (even, depending on how that value is used, MySQL injections). 尽管其他人说使用客户端通过诸如javascript中存储的数据库版本之类的变量来检测更改,但我还是建议您将服务器留在服务器端,这是因为知道如何注入javascript的人将能够更改该值,这可能会产生不良或什至是恶意的结果(甚至取决于MySQL注入如何使用该值)。

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