如何递归遍历目录以删除具有某些扩展名的文件

Question

I need to loop through a directory recursively and remove all files with extension .pdf and .doc . I'm managing to loop through a directory recursively but not managing to filter the files with the above mentioned file extensions.

My code so far

#/bin/sh

SEARCH_FOLDER="/tmp/*"

for f in $SEARCH_FOLDER
do
    if [ -d "$f" ]
    then
        for ff in $f/*
        do      
            echo "Processing $ff"
        done
    else
        echo "Processing file $f"
    fi
done

I need help to complete the code, since I'm not getting anywhere.

Answer 1

As a followup to mouviciel's answer, you could also do this as a for loop, instead of using xargs. I often find xargs cumbersome, especially if I need to do something more complicated in each iteration.

for f in $(find /tmp -name '*.pdf' -or -name '*.doc'); do rm $f; done

As a number of people have commented, this will fail if there are spaces in filenames. You can work around this by temporarily setting the IFS (internal field seperator) to the newline character. This also fails if there are wildcard characters \\[?* in the file names. You can work around that by temporarily disabling wildcard expansion (globbing).

IFS=$'\n'; set -f
for f in $(find /tmp -name '*.pdf' -or -name '*.doc'); do rm "$f"; done
unset IFS; set +f

If you have newlines in your filenames, then that won't work either. You're better off with an xargs based solution:

find /tmp \( -name '*.pdf' -or -name '*.doc' \) -print0 | xargs -0 rm

(The escaped brackets are required here to have the -print0 apply to both or clauses.)

GNU and *BSD find also has a -delete action, which would look like this:

find /tmp \( -name '*.pdf' -or -name '*.doc' \) -delete

Answer 2

find就是为此而生的。

find /tmp -name '*.pdf' -or -name '*.doc' | xargs rm

Answer 3

Without find :

for f in /tmp/* tmp/**/* ; do
  ...
done;

/tmp/* are files in dir and /tmp/**/* are files in subfolders. It is possible that you have to enable globstar option ( shopt -s globstar ). So for the question the code should look like this:

shopt -s globstar
for f in /tmp/*.pdf /tmp/*.doc tmp/**/*.pdf tmp/**/*.doc ; do
  rm "$f"
done

Note that this requires bash ≥4.0 (or zsh without shopt -s globstar , or ksh with set -o globstar instead of shopt -s globstar ). Furthermore, in bash <4.3, this traverses symbolic links to directories as well as directories, which is usually not desirable.

Answer 4

If you want to do something recursively, I suggest you use recursion (yes, you can do it using stacks and so on, but hey).

recursiverm() {
  for d in *; do
    if [ -d "$d" ]; then
      (cd -- "$d" && recursiverm)
    fi
    rm -f *.pdf
    rm -f *.doc
  done
}

(cd /tmp; recursiverm)

That said, find is probably a better choice as has already been suggested.

Answer 5

This doesn't answer your question directly, but you can solve your problem with a one-liner:

find /tmp \( -name "*.pdf" -o -name "*.doc" \) -type f -exec rm {} +

Some versions of find (GNU, BSD) have a -delete action which you can use instead of calling rm :

find /tmp \( -name "*.pdf" -o -name "*.doc" \) -type f -delete

Answer 6

Here is an example using shell ( bash ):

#!/bin/bash

# loop & print a folder recusively,
print_folder_recurse() {
    for i in "$1"/*;do
        if [ -d "$i" ];then
            echo "dir: $i"
            print_folder_recurse "$i"
        elif [ -f "$i" ]; then
            echo "file: $i"
        fi
    done
}


# try get path from param
path=""
if [ -d "$1" ]; then
    path=$1;
else
    path="/tmp"
fi

echo "base path: $path"
print_folder_recurse $path

Answer 7

This method handles spaces well.

files="$(find -L "$dir" -type f)"
echo "Count: $(echo -n "$files" | wc -l)"
echo "$files" | while read file; do
  echo "$file"
done

Edit, fixes off-by-one

function count() {
    files="$(find -L "$1" -type f)";
    if [[ "$files" == "" ]]; then
        echo "No files";
        return 0;
    fi
    file_count=$(echo "$files" | wc -l)
    echo "Count: $file_count"
    echo "$files" | while read file; do
        echo "$file"
    done
}

Answer 8

For bash (since version 4.0):

shopt -s globstar nullglob dotglob
echo **/*".ext"

That's all.
The trailing extension ".ext" there to select files (or dirs) with that extension.

Option globstar activates the ** (search recursivelly).
Option nullglob removes an * when it matches no file/dir.
Option dotglob includes files that start wit a dot (hidden files).

Beware that before bash 4.3, **/ also traverses symbolic links to directories which is not desirable.

Answer 9

The following function would recursively iterate through all the directories in the \\home\\ubuntu directory( whole directory structure under ubuntu ) and apply the necessary checks in else block.

function check {
        for file in $1/*      
        do
        if [ -d "$file" ]
        then
                check $file                          
        else
               ##check for the file
               if [ $(head -c 4 "$file") = "%PDF" ]; then
                         rm -r $file
               fi
        fi
        done     
}
domain=/home/ubuntu
check $domain

Answer 10

There is no reason to pipe the output of find into another utility. find has a -delete flag built into it.

find /tmp -name '*.pdf' -or -name '*.doc' -delete

Answer 11

This is the simplest way I know to do this: rm **/@(*.doc|*.pdf)

** makes this work recursively

@(*.doc|*.pdf) looks for a file ending in pdf OR doc

Easy to safely test by replacing rm with ls

Answer 12

The other answers provided will not include files or directories that start with a . the following worked for me:

#/bin/sh
getAll()
{
  local fl1="$1"/*;
  local fl2="$1"/.[!.]*; 
  local fl3="$1"/..?*;
  for inpath in "$1"/* "$1"/.[!.]* "$1"/..?*; do
    if [ "$inpath" != "$fl1" -a "$inpath" != "$fl2" -a "$inpath" != "$fl3" ]; then 
      stat --printf="%F\0%n\0\n" -- "$inpath";
      if [ -d "$inpath" ]; then
        getAll "$inpath"
      #elif [ -f $inpath ]; then
      fi;
    fi;
  done;
}

Answer 13

I think the most straightforward solution is to use recursion, in the following example, I have printed all the file names in the directory and its subdirectories.

You can modify it according to your needs.

#!/bin/bash    
printAll() {
    for i in "$1"/*;do # for all in the root 
        if [ -f "$i" ]; then # if a file exists
            echo "$i" # print the file name
        elif [ -d "$i" ];then # if a directroy exists
            printAll "$i" # call printAll inside it (recursion)
        fi
    done 
}
printAll $1 # e.g.: ./printAll.sh .

OUTPUT:

> ./printAll.sh .
./demoDir/4
./demoDir/mo st/1
./demoDir/m2/1557/5
./demoDir/Me/nna/7
./TEST

It works fine with spaces as well!

Note : You can use echo $(basename "$i") # print the file name to print the file name without its path.

OR : Use echo ${i%/##*/}; # print the file name echo ${i%/##*/}; # print the file name which runs extremely faster, without having to call the external basename .

Answer 14

就做

find . -name '*.pdf'|xargs rm

Answer 15

以下将递归遍历给定目录并列出所有内容：

for d in /home/ubuntu/*; do echo "listing contents of dir: $d"; ls -l $d/; done

Answer 16

If you can change the shell used to run the command, you can use ZSH to do the job.

#!/usr/bin/zsh

for file in /tmp/**/*
do
    echo $file
done

This will recursively loop through all files/folders.