[英]Split a string by two characters
Firstable i want to match if a string has the following format: $abc #xyz
or $abc .xyz
. 首先,如果字符串具有以下格式,我想进行匹配: $abc #xyz
或$abc .xyz
。
The abc and xyz mean only alphanumeric string. abc和xyz仅表示字母数字字符串。
If it's matched then i need to extract the first $abc
and the last #xyz
, all that using pure javascript and maybe regex. 如果匹配,那么我需要提取第一个$abc
和最后一个#xyz
,所有这些都使用纯JavaScript以及正则表达式。
The pattern is in the following order: 模式按以下顺序:
Thanks in advance for any help. 在此先感谢您的帮助。
Try the following regular expression: 尝试以下正则表达式:
/^(\$[a-zA-Z\d]+) ([#.][a-zA-Z\d]+)$/
Explanation: 说明:
^ Start of line. ( Start capturing group. \$ Literal dollar sign. [a-zA-Z\d] Any letter in a-z or A-Z, or any digit. + One or more of the previous. ) End capturing group. <space> Literal space. ( Start second capturing group. [#.] Either a number sign or a period. [a-zA-Z\d]+ ) End second capturing group. $ End of line.
Example usage: 用法示例:
> var s = '$abc #xyz';
> s.match(/^(\$[a-zA-Z\d]+) ([#.][a-zA-Z\d]+)$/);
["$abc #xyz", "$abc", "#xyz"]
Like this? 像这样?
if(str.match(/^\$[a-z0-9]+ (#|\.)[a-z0-9]+$/i)) {
var parts = str.split(' ');
}
Update: Obviously there a various ways to achieve this. 更新:显然有多种方法可以实现此目的。 There is not the one regular expression. 没有一个正则表达式。 If you make use of capture groups, you can extract the strings even in one step ( like Mark showed in his answer ). 如果您使用捕获组,则即使一步也可以提取字符串( 如Mark在其答案中所示 )。
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