bash shell脚本函数定义（例如“ f（）{}”）中使用的括号是什么？ 与使用“功能”关键字不同吗？

Question

I'v always wondered what they're used for? Seems silly to put them in every time if you can never put anything inside them.

function_name () {
    #statements
}

Also is there anything to gain/lose with putting the function keyword at the start of a function?

function function_name () {
    #statements
}

Answer 1

The keyword function has been deprecated in favor of function_name() for portability with the POSIX spec

A function is a user-defined name that is used as a simple command to call a compound command with new positional parameters. A function is defined with a "function definition command".

The format of a function definition command is as follows:

 fname() compound-command[io-redirect ...] 

Note that the { } are not mandatory so if you're not going to use the keyword function (and you shouldn't) then the () are necessary so the parser knows you're defining a function.

Example, this is a legal function definition and invocation:

$ myfunc() for arg; do echo "$arg"; done; myfunc foo bar
foo
bar

Answer 2

The empty parentheses are required in your first example so that bash knows it's a function definition (otherwise it looks like an ordinary command). In the second example, the () is optional because you've used function .

Answer 3

Without function , alias expansion happens at definition time . Eg:

alias a=b
# Gets expanded to "b() { echo c; }" :
a() { echo c; }
b
# => c
# Gets expanded to b:
a
# => c

With function however, alias expansion does not happen at definition time, so the alias "hides" the definition:

alias a=b
function a { echo c; }
b
# => command not found
# Gets expanded to b:
a
# => command not found
unalias a
a
# => c