为什么在函数中有“静态”定义？

Question

Considering the example at http://c-faq.com/misc/hexio.html , what is the reason to have an additional pointer to a 'static' character buffer? Why can't we get away with retbuf ?

Answer 1

Without the static keyword, the buffer would be allocated on the stack -- and deallocated by the time the function returns to the caller.

Using static ensures the buffer is valid after the function returns.

Answer 2

You need a pointer so you can store a changing address. If you just had retbuf , you would have to design the function to use a changing index variable. Eg:

int ind = sizeof(retbuf)-1;
retbuf[ind] = '\0';

etc.

Note that arrays are not pointers. An array is a fixed-size region of memory. A pointer is an address.