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如何使用php编辑xml子节点

[英]How to Edit xml child node with php

i already search here before i ask this question.. I know there is an answer here somewhere.. but i can't find it.. 在问这个问题之前,我已经在这里搜索了。我知道这里有一个答案..但是我找不到它。

I want to be able to edit child node by id in my xml file.. i tried alot of script but i'm having a really bad time with this.. 我希望能够通过我的xml文件中的ID编辑子节点。.我尝试了很多脚本,但是与此同时,我的时间很不好。

please see this line in edit.php: 请在edit.php中看到这一行:

echo "the problem is in the next line";

this is the last line that the server reads.. 这是服务器读取的最后一行。

thanks you for your help. 谢谢您的帮助。

events.xml events.xml

<?xml version="1.0" encoding="UTF-8" ?>
<events>
    <record>
        <id>1</id>
        <event>a</event>
        <eventDate>a</eventDate>
        <desc>a</desc>
    </record>
    <record>
        <id>2</id>
        <event>b</event>
        <eventDate>b</eventDate>
        <desc>b</desc>
    </record>
</events>

edit.php edit.php

header("Content-type: text/html; charset=utf-8");

$record = array(
    'id' => $_POST['id'],
    'event' => $_POST['event'],
    'eventDate' => $_POST['eventDate'],
    'desc' => $_POST['desc'],
);

$id = $record["id"];
$dom = new DOMDocument;
$dom->load('events.xml');

$xpath = new DOMXPath($dom);
$query = sprintf('/events/record[./id = "%d"]', $id);

foreach($xpath->query($query) as $record) {

    $eventN = $record->parentNode->getElementsByTagName("event");
    echo "the problem is in the next line";
    $eventN->item(0)->nodeValue = $record["event"];

    $dateN = $record->parentNode->getElementsByTagName("eventDate");
    $dateN->item(0)->nodeValue = $record["eventDate"];

    $descN = $record->parentNode->getElementsByTagName("desc");
    $descN->item(0)->nodeValue = $record["desc"];

}
$dom->save("events.xml");
header("Location: {$_SERVER['HTTP_REFERER']}");
?>

Edited: Working edit.php but not dynamic 编辑:工作edit.php,但不是动态的

<?php
header("Content-type: text/html; charset=utf-8");

$record = array(
    'id' => $_POST['id'],
    'event' => $_POST['event'],
    'eventDate' => $_POST['eventDate'],
    'desc' => $_POST['desc'],
);

$id = $record["id"];
$dom = new DOMDocument;
$dom->load('events.xml');

$xpath = new DOMXPath($dom);
$query = sprintf('/events/record[./id = "%d"]', $id);

foreach($xpath->query($query) as $record) {

    $eventN = $record->parentNode->getElementsByTagName("event");
    echo "i change it to string text and it's works. ";
    $eventN->item(0)->nodeValue = 'text';

    $dateN = $record->parentNode->getElementsByTagName("eventDate");
    $dateN->item(0)->nodeValue = 'text';

    $descN = $record->parentNode->getElementsByTagName("desc");
    $descN->item(0)->nodeValue = 'text';

}
$dom->save("events.xml");
header("Location: {$_SERVER['HTTP_REFERER']}");
?>

Ok, the issue is your $record array from the beginning is overwritten in the foreach . 好的,问题是您的$record数组从一开始就被foreach覆盖了。

替代文字

Either change the as $record or change the name of the array holding the $_POST data. 可以将as更改为$record也可以更改保存$_POST数据的数组的名称。

On a sidenote, you are iterating over elements, so there is no reason to get to the parentNode. 在旁注中,您正在遍历元素,因此没有理由进入parentNode。 Use 采用

$record->getElementsByTagName("event");

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