[英]php regex - Delete phrase
I have a long string that has imbedded in it: "ABC_1_"
and "ABC_2_"
and "ABC_3_"
etc. 我有一个长字符串嵌入其中:
"ABC_1_"
, "ABC_2_"
和"ABC_3_"
等。
For example: 例如:
"lorum ipsum ABC_1_ doit more ABC_3_ and so on".
I need to write a PHP preg_replace that will remove the 6 characters ( ABC_xx
) if the first 4 are "ABC_"
and return the full remaining string, in my example: 我需要编写一个PHP preg_replace,如果前4个字符是
"ABC_"
,它将删除6个字符( ABC_xx
),并返回完整的剩余字符串,在我的示例中:
"lorum ipsum doit more and so on".
Thanks! 谢谢!
Use preg_replace with regular expression: (ABC_.{2} )
对正则表达式使用preg_replace:
(ABC_.{2} )
$string = "lorum ipsum ABC_1_ doit more ABC_3_ and so on";
$pattern = "/(ABC_.{2})/";
$replacement = "";
echo preg_replace($pattern, $replacement, $string);
Try this: 尝试这个:
$s = preg_replace('/\bABC_../', '', $s);
The \\b
matches a word boundary, and the dots match any character (apart from new line). \\b
匹配单词边界,点匹配任何字符(除了新行)。
Full example: 完整示例:
<?php
$s = 'ABC_1_foo lorum ipsum ABC_1_ doit more ABC_3_ and so on';
$s = preg_replace('/\bABC_../', '', $s);
echo $s;
?>
Result: 结果:
foo lorum ipsum doit more and so on
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