Java System.in问题

Question

public static void main(String[] args) {

    Scanner sc = new Scanner(System.in);

           while (sc.hasNext()) {

               if (sc.next().equals("exit")){
                   System.out.println("EXITING");
                   System.exit(0);
               }  else {
                   System.out.println("IM STILL WORKING ok?");
               }

            }

    }
}

So here is a piece of code i was writing the other day to try and figure sth out (doesn't really matter what). The result of executing this code is :

eIM STILL WORKING ok?

eIM STILL WORKING ok?

exit

IM STILL WORKING ok?

exit

EXITING

Can somebody kindly explain why this has happened? I mean the fact the the Scanner didnt capture the first occurence of the word exit.

Answer 1

This code is correct, and it works for me -- are you sure you've got the latest code compiled and running?

e
IM STILL WORKING ok?
e
IM STILL WORKING ok?
e
IM STILL WORKING ok?
ex
IM STILL WORKING ok?
exit
EXITING

Answer 2

I think i know what the problem is . reproduced it right now... pressed several time a button for input (button e) followed by a fast return button (enter). This is why some lines have both the input and output. after that Scanner is unable to get the first occurrence of exit. It doesn't make that much sense to me tho as I think what I did shouldn't cause any trouble.