Java rmi注册表中远程对象的可能名称是什么？

Question

What are the possible names of remote objects in a java rmi registry? Are there forbidden characters?

I try to call the rebind method of the class Naming to bind an object in an rmi registry and I get a MalformedUrlException . I know that the problem is the name of the object because when I use a name like abc it works , so you probably don't need a stack trace to answer.

The thing is that the name is pseudorandomly generated.For example one of the names that caused the problem is [B@f3d6a5 . Is there a way to use whatever name you like and if not then what are the permitted names?

This is strange because the api does not state any rules about the name ,you can see it here . Maybe some characters that appear in the names ,like [ , have to be escaped with \\ . Maybe it is not about java but about url specifications , if there are any , in which case I probably will have to use other names.

Answer 1

该API当然没有说明任何限制，但是如果您遇到MalformedUrlException ，我将尝试对随机生成的名称进行URLEncode 。

Answer 2

The javadocs state:

name - a name in URL format (without the scheme component)

If you take a look at the source code for Naming you will see that it converts thename you pass in into a URI and throws a MalformedURLException on certain conditions.

private static ParsedNamingURL intParseURL(String str)
    throws MalformedURLException, URISyntaxException
{
    URI uri = new URI(str);
    if (uri.isOpaque()) {
        throw new MalformedURLException(
        "not a hierarchical URL: " + str);
    }
    if (uri.getFragment() != null) {
        throw new MalformedURLException(
        "invalid character, '#', in URL name: " + str);
    } else if (uri.getQuery() != null) {
        throw new MalformedURLException(
        "invalid character, '?', in URL name: " + str);
    } else if (uri.getUserInfo() != null) {
        throw new MalformedURLException(
        "invalid character, '@', in URL host: " + str);
    }

This means that the name must be a valid URI and, an in addition, cannot contain # , ? or @ .

Take a look at the code yourself for more details.