在自己的cmd.exe中运行工具

Question

I am working on a Java application which will be used to launch other applications. Now, most of those have a GUI, but some are command-line tools. For the latter, I would like to open the appropriate command line and have them execute there.

That is, on Windows, I would like to open cmd.exe, and run the tool with the appropriate arguments. The problem is getting cmd.exe to stay open.

When I use ProcessBuilder to start

cmd.exe /k java -version

I get the desired output (I capture the output streams), but the cmd.exe window isn't visible.

When I run

cmd.exe /k start java -version

the cmd.exe window pops up for a split second and then disappears.

But when I just run cmd.exe /k start the cmd.exe window appears and stays open, while cmd.exe start doesn't show a window (as I would expect).

What I want is for the command line tool to run in its own cmd.exe and stay open for input.

Answer 1

Running this from the cmd.exe works.

cmd start cmd /k java -version

However, this just waits for you to run more cmd's.

If you want it to wait for user input use

cmd start java MyProgramWhichWaitsForInput

Answer 2

This was solved using the answer in "Starting a Java tool with cmd.exe" . I suspected the problems were separate, but they were not.