将NSString转换为NSInteger？

Question

我想将string data转换为NSInteger 。

Answer 1

如果字符串是数字的人类可读表示，则可以执行以下操作：

NSInteger myInt = [myString intValue];

Answer 2

[myString intValue] returns a cType "int"

[myString integerValue] returns a NSInteger .

In most cases I do find these simple functions by looking at apples class references, quickest way to get there is click [option] button and double-click on the class declarations (in this case NSString ).

Answer 3

我发现这是正确的答案。

NSInteger myInt = [someString integerValue];

Answer 4

NSNumber *tempVal2=[[[NSNumberFormatter alloc] init] numberFromString:@"your text here"];

returns NULL if string or returns NSNumber

NSInteger intValue=[tempVal2 integerValue];

returns integer of NSNumber

Answer 5

int myInt = [myString intValue];
NSLog(@"Display Int Value:%i",myInt);

Answer 6

this is safer than integerValue:

-(NSInteger)integerFromString:(NSString *)string
{
    NSNumberFormatter *formatter=[[NSNumberFormatter alloc]init];
    [formatter setNumberStyle:NSNumberFormatterDecimalStyle];
    NSNumber *numberObj = [formatter numberFromString:string];
    return [numberObj integerValue];
}

Answer 7

NSString *string = [NSString stringWithFormat:@"%d", theinteger];