如何为mysql_query返回数组？

Question

  // make empty array
  $sqlArray=array();
  $jsonArray=array();


  // START NEED FAST WORKING ALTERNATİVES -----------------------------------------------------
  // first 20 vistors
  $query = "SELECT user_id FROM vistors LIMIT 20"; 
  $result = mysql_query ($query) or die ($query);

  // make vistors user query array
  while ($vstr_line = mysql_fetch_array($result)){
    array_push($sqlArray, $vstr_line['user_id']);
  }

  // implode vistors user array
  $sqlArray_impl = implode("', '", $sqlArray);
 // END NEED FAST WORKING ALTERNATİVES -----------------------------------------------------


  // Get vistors information
  $query = "SELECT id, username, picture FROM users WHERE id IN ('$sqlArray_impl')"; 
  $qry_result = mysql_query($query) or die($query);


  while ($usr_line = mysql_fetch_array($qry_result)){
    array_push($jsonArray, $usr_line['id'].' - '.$usr_line['username'].' - '.$usr_line['picture']);
  }


  print_r($sqlArray);

  echo '<br><br>';

  print_r($jsonArray);

see this my functions.. i need a replacement for fast working alternatives..

function within the range specified above, to me, running faster than the alternative. the query will return back array ?

thx for all helpers !

Answer 1

1. Can you use a JOIN or SUB SELECT to reduce the query count from 2 to 1? Might not give much of a boost but worth a shot and a cleaner implementation.

2. Where is the bottleneck? Most likely the db and not the php code.

3. Are the tables/columns properly indexed? Run EXPLAIN on both queries.

Answer 2

Easiest would be to include first query as subquery eliminating one turn to the DB and a lot of code:

  // Get vistors information
  $query = "SELECT id, username, picture FROM users WHERE id IN (SELECT user_id FROM vistors LIMIT 20)"; 
  $qry_result = mysql_query($query) or die($query);

Unless there is more reason to have the first one seperate, but that is not visible in your code example.

Answer 3

If you use PDO (recommended anyway...), you can return the result array all at once using fetchAll() .

For your second query, you can use string concatenation in MySQL to directly return the result you want.