无法查看网页的 HTML 源代码
[英]Unable to view the HTML source code of a web page
问题描述
Could you please post the HTML source code of this web page:
能否请您发布此网页的 HTML 源代码：
http://www.xuanyinwen.com/test3.html http://www.xuanyinwen.com/test3.html
I just cannot figure out how to retrieve it..我只是不知道如何检索它..
6 个解决方案
解决方案1
4 已采纳 2011-01-26 21:53:01
解决方案2
2 2011-01-26 21:54:30
Just use "View source" option from tool menu in browser.只需使用浏览器工具菜单中的“查看源代码”选项即可。
<head>
<script language="JavaScript">
var password;
var pass1="wen";
password = prompt('Whats The Magic Word?',' ');
if (password === pass1)
alert('That Is Correct!');
else
window.location="SITE-LINK";
</script>
</head>
<body onLoad="ImageBook()">
TEST
</body>
</html>
解决方案3
1 2011-01-26 21:55:17
"Right-Click + Save Link/Target As..." can be helpful sometimes :) There are several methods of doing this. “右键单击 + 将链接/目标另存为...”有时会很有帮助:) 有几种方法可以做到这一点。
<head>
<script language="JavaScript">
var password;
var pass1="wen";
password = prompt('Whats The Magic Word?',' ');
if (password === pass1)
alert('That Is Correct!');
else
window.location="SITE-LINK";
</script>
</head>
<body onLoad="ImageBook()">
TEST
</body>
</html>
解决方案4
0 2011-01-26 21:55:13
Either disable JavaScript on your browser, or use some kind of command line tool (eg curl).要么禁用浏览器上的 JavaScript，要么使用某种命令行工具（例如 curl）。
<head>
<script language="JavaScript">
var password;
var pass1="wen";
password = prompt('Whats The Magic Word?',' ');
if (password === pass1)
alert('That Is Correct!');
else
window.location="SITE-LINK";
</script>
</head>
<body onLoad="ImageBook()">
TEST
</body>
</html>
解决方案5
0 2011-01-26 21:58:35
在 firefox 中使用 firebug 并选择脚本。
<head>
<script language="JavaScript">
var password;
var pass1="wen";
password = prompt('Whats The Magic Word?',' ');
if (password === pass1)
alert('That Is Correct!');
else
window.location="SITE-LINK";
</script>
</head>
<body onLoad="ImageBook()">
TEST
</body>
</html>
解决方案6
0 2020-03-15 09:07:00
在 Windows 10 中输入键盘 Ctrl + U
声明:本站的技术帖子网页，遵循CC BY-SA 4.0协议，如果您需要转载，请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.