获取Castle-Monorail网站的当前会话？

Question

I'm modifying a Castle-Monorail site that I've inherited and found that it would be useful to see a list of currently online users. Currently there are Filters that determine who can access which parts of the site so I can distinguish logged in sessions from non-logged in sessions. Is there an easy way of getting a list of active sessions so that I could then work out who is logged in?

Answer 1

我相信没有简单的方法，除非您将用户登录信息存储在数据库或应用程序变量中，否则您将无法知道有多少活动会话。

Answer 2

Here's the solution I ended up with:

(With help from: https://stackoverflow.com/q/1470571/126785 and Ken Egozi's comments)

In Global.asax.cs:

private static readonly object padlock = new object();
private static Dictionary<string,SessionData> sessions = new Dictionary<string,SessionData>();
public static Dictionary<string, SessionData> Sessions
{
    get { lock (padlock) { return sessions; } }
}

public struct SessionData
{
    public string Name { get; set; }
    public int AccountId { get; set; }
    public string CurrentLocation { get; set; }
}

protected void Session_Start(object sender, EventArgs e)
{
    Sessions.Add(Session.SessionID, new SessionData());
}

protected void Session_End(object sender, EventArgs e)
{
    Sessions.Remove(Session.SessionID);
}

public static void SetSessionData(string sessionId, int accountId, string name, string currentLoc)
{
    Sessions.Remove(sessionId);
    Sessions.Add(sessionId, new SessionData { AccountId = accountId, CurrentLocation = currentLoc, Name = name });
}

public static void SetCurrentLocation(string sessionId, string currentLoc)
{
    SessionData currentData = Sessions[sessionId];
    Sessions.Remove(sessionId);
    Sessions.Add(sessionId, new SessionData { AccountId = currentData.AccountId, CurrentLocation = currentLoc, Name = currentData.Name });
}

Then when logging in:

Global.SetSessionData(((HttpSessionStateContainer)Session.SyncRoot).SessionID,account.Id,account.Name,"Logged In");

Now I just need to work out the best place to update the location from. Calls from each function could be a bit tiresome!