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onLost焦点事件不起作用-ms访问

[英]onLost focus Event is not working -ms access

This code is not working. 此代码无效。 Can anyone help me out? 谁能帮我吗?

Private Sub txtErrorComment_5_LostFocus()

    If IsEmpty(Me.txtErrorComment_5) Then
        MsgBox "Eh..! It cannot be Empty."
    End If

End Sub

txtErrorComment_5 is probably Null - which evaluates to False when run through IsEmpty() - yes, this is un-intuitive, but whenever you compare to Null, the result is false. txtErrorComment_5可能为Null-通过IsEmpty()运行时其值为False-是的,这是不直观的,但是每当与Null比较时,结果均为false。

Try the following: 请尝试以下方法:

Private Sub txtErrorComment_5_LostFocus()

    If IsEmpty(Me.txtErrorComment_5) or IsNull(Me.txtErrorComment_5) Then
        MsgBox "Eh..! It cannot be Empty."
    End If

End Sub

Or just: 要不就:

Private Sub txtErrorComment_5_LostFocus()

    If IsNull(Me.txtErrorComment_5) Then
        MsgBox "Eh..! It cannot be Empty."
    End If

End Sub

IsNull can handle Null's IsNull可以处理Null

Edit: 编辑:

@David-W-Fenton is correct. @ David-W-Fenton是对的。 The better way to do this BeforeUpdate (not LostFocus) 更好的方法是使用BeforeUpdate(不是LostFocus)

Private Sub txtErrorComment_5_BeforeUpdate(Cancel As Integer)

     If IsNull(Me.txtErrorComment_5) Then
         MsgBox "Eh..! It cannot be Empty."
         Cancel=true
     End If

End Sub

To detect whether txtErrorComment_5 is blank, concatenate a Null string to its value and see whether the character length of the combined expression is zero. 若要检测txtErrorComment_5是否为空,请将Null字符串连接为其值,并查看组合表达式的字符长度是否为零。

Private Sub txtErrorComment_5_LostFocus()
    If Len(Me.txtErrorComment_5 & vbNullString) = 0 Then
        MsgBox "Eh..! It cannot be Empty."
    End If
End Sub

If you want txtErrorComment_5 treated as blank when it contains only one or more space characters, include the Trim() function. 如果您希望txtErrorComment_5在仅包含一个或多个空格字符时视为空白,请包含Trim()函数。

Private Sub txtErrorComment_5_LostFocus()
    If Len(Trim(Me.txtErrorComment_5) & vbNullString) = 0 Then
        MsgBox "Eh..! It cannot be Empty."
    End If
End Sub

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