使用正则表达式在JavaScript中拆分字符串

Question

I'm trying to write a regex for use in javascript.

var script = "function onclick() {loadArea('areaog_og_group_og_consumedservice', '\x26roleOrd\x3d1');}";
var match = new RegExp("'[^']*(\\.[^']*)*'").exec(script);

I would like split to contain two elements:

match[0] == "'areaog_og_group_og_consumedservice'";

match[1] == "'\x26roleOrd\x3d1'";

This regex matches correctly when testing it at gskinner.com/RegExr/ but it does not work in my Javascript. This issue can be replicated by testing ir here http://www.regextester.com/ .

I need the solution to work with Internet Explorer 6 and above.

Can any regex guru's help?

Answer 1

Judging by your regex, it looks like you're trying to match a single-quoted string that may contain escaped quotes. The correct form of that regex is:

'[^'\\]*(?:\\.[^'\\]*)*'

(If you don't need to allow for escaped quotes, /'[^']*'/ is all you need.) You also have to set the g flag if you want to get both strings. Here's the regex in its regex-literal form:

/'[^'\\]*(?:\\.[^'\\]*)*'/g

If you use the RegExp constructor instead of a regex literal, you have to double-escape the backslashes: once for the string literal and once for the regex. You also have to pass the flags ( g , i , m ) as a separate parameter:

var rgx = new RegExp("'[^'\\\\]*(?:\\\\.[^'\\\\]*)*'", "g");
while (result = rgx.exec(script))
    print(result[0]);

Answer 2

也许这样：

'([^']*)'\s*,\s*'([^']*)'

Answer 3

The regex you're looking for is .*?('[^']*')\\s*,\\s*('[^']*') . The catch here is that, as usual, match[0] is the entire matched text (this is very normal) so it's not particularly useful to you. match[1] and match[2] are the two matches you're looking for.

var script = "function onclick() {loadArea('areaog_og_group_og_consumedservice', '\x26roleOrd\x3d1');}";
var parameters = /.*?('[^']*')\s*,\s*('[^']*')/.exec(script);
alert("you've done: loadArea("+parameters[1]+", "+parameters[2]+");");

The only issue I have with this is that it's somewhat inflexible. You might want to spend a little time to match function calls with 2 or 3 parameters?

EDIT In response to you're request, here is the regex to match 1,2,3,...,n parameters. If you notice, I used a non-capturing group (the (?: ) part) to find many instances of the comma followed by the second parameter.

/.*?('[^']*')(?:\s*,\s*('[^']*'))*/