使用PHP cURL搜索结果的网页 - 发布不起作用

Question

I'm new to using cURL, but from what I have read, the following should post the variables to the page, then print the result. The result prints, but it doesn't seem like the POST variables went because no results are generated. FireBug doesn't show anything going either. Any ideas what I'm doing wrong?

Thanks for your help!

 // create curl resource
        $ch = curl_init();

        // set url
        curl_setopt($ch, CURLOPT_URL, "http://butlercountyclerk.org/bcc-11112005/ForeclosureSearch.aspx");


        $data = array(
            'Search:btnSearch' => 'Search',
            'Search:ddlMonth' => '1',
            'Search:ddlYear' => '2011'
        );


        curl_setopt($ch, CURLOPT_POST, 1);
        curl_setopt($ch, CURLOPT_POSTFIELDS, $data); 

        //return the transfer as a string
        curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);

        // $output contains the output string
        $output = curl_exec($ch);

        // close curl resource to free up system resources
        curl_close($ch);

        echo $output;

Answer 1

Based on the coding of the site, it appears that you're missing a number of variables. Take for example, the actual post request made to the search page:

__VIEWSTATE=dDwtMjk2Mjk5NzczO3Q8O2w8aTwxPjs+O2w8dDw7bDxpPDE+Oz47bDx0PDtsPGk8Mz47aTwxOT47PjtsPHQ8dDw7cDxsPGk8MD47aTwxPjtpPDI+O2k8Mz47aTw0PjtpPDU+Oz47bDxwPDIwMDY7MjAwNj47cDwyMDA3OzIwMDc+O3A8MjAwODsyMDA4PjtwPDIwMDk7MjAwOT47cDwyMDEwOzIwMTA+O3A8MjAxMTsyMDExPjs+Pjs+Ozs+O3Q8QDA8Ozs7Ozs7Ozs7Oz47Oz47Pj47Pj47Pj47PmVlaXw5JK161vti9TC+QMdeTNQI&Search:ddlMonth=1&Search:ddlYear=2011&Search:txtCompanyName=&Search:txtLastName=&Search:txtCaseNumber=&Search:btnSearch=Search

This is post-feeding though URLDecode by the way. What this means though, is that your array of 3 values is missing data. At the very least, I'd suspect that Search:btnSearch=Search is missing, and would suggest that you implement all fields into your POST request.