匹配x正则表达式或y正则表达式

Question

I currently have this:

^(.+)\(\w+\)|^(.+)\s\(\d{3}\:\d{3}\s\-\s\d{3}\:\d{3}\)

The #1 it only matches Foo's
#2 Foo has which is correct
#3 does match foo but it's in the 3rd array item [2]:

3rd array output:
    (
        [0] => Foo (100:200 - 300:400)
        [1] => 
        [2] => Foo
    ) 

The bold is what I'm trying to match:
Foo's (match11) this (100:200 - 300:400) the end #1
Foo has (not_matched) (100:200 - 300:400) the end #2
Foo (100:200 - 300:400) the end #3
note: im not trying to match the #1,#2,#3 at the end of each line, thats just for reference.

If "(100:200 - 300:400)" is found then get any text in front of it, elseif "(not_matched) (100:200 - 300:400)" found then get any text in front of it, else get text in front of "(100:200 - 300:400)"

The elseif part "(not_matched) (100:200 - 300:400)" can be identified as it only has 1 white space between the 2 round brackets of not_matched and (100:200 - 300:400)


Edit:

This is what i'v come up with which does seem to work, though it requires some workarounds in php to be useful.

(.+)\s\(\w+\)\s\(|(.+)\s\(\d{3}\:\d{3}\s\-\s\d{3}\:\d{3}\)

Working example: http://www.rubular.com/r/NSpGcnyg0p
For some reason it doesn't seem to save my example, so you will have to copy/paste it in.

But the regex doesn't have a direct match on each of them, thats why I have to remove the empty array element in php so that I get the result in the [1] element.

Can anyone see what I'm doing wrong in my regex?

Answer 1

Try this:

^.*?(?=\s*(?:\(not_matched\)\s)?\(\d+:\d+\s*-\s*\d+:\d+\))

or, in PHP:

if (preg_match(
    '/^                   # Anchor the match at start of line
    .*?                   # Match any number of characters lazily
    (?=                   # until just before the following:
     \s*                  # - optional whitespace
     (?:                  # - the following group:
      \(not_matched\)\s   #    - literal (not_matched), followed by 1 whitespace
     )?                   #   (which is optional)
     \(\d+:\d+\s*-\s*\d+:\d+\) # a group like (nnn:mmm - ooo:ppp)
    )                     # End of lookahead assertion
    /x', 
    $subject, $regs)) {
    $result = $regs[0];
} else {
    $result = "";
}

Answer 2

This will match your second example: (.+)(\\([\\D]+\\).+)(\\#\\d+) .

And this one will match two others: (.+)(\\([\\d\\W]+\\).+)(\\#\\d+) .

Answer 3

如果我清楚地明白，这应该是诀窍：

/^(.+)(?:\(not_matched\)\s)?(?:\(\d+:\d+\s-\s\d+:\d+\))\s.+\s(#\d+)$/i

Answer 4

This does seem to work, but needs a little workaround to be useful in php. (read my original question).

I'll select this as the answer if no one else has any ideas...

(.+)\s\(\w+\)\s\(|(.+)\s\(\d{3}\:\d{3}\s\-\s\d{3}\:\d{3}\)

Answer 5

The following pattern will match everything, the result is stored into the wanted key :

$PATTERN = '/
    (?P<wanted>.*?)\s* # everything
    (\(.+\s.+\)\s+)? # maybe followed by
    (?= # that ends with
        \(\d{3}:\d{3}\s-\s\d{3}:\d{3}\)
    )
    /x';
preg_match($PATTERN, "Foo's (match11) this (100:200 - 300:400) the end", $matches);
var_dump($matches['wanted']);
preg_match($PATTERN, "Foo has (not matched) (100:200 - 300:400) the end", $matches);
var_dump($matches['wanted']);
preg_match($PATTERN, "Foo (100:200 - 300:400) the end", $matches);
var_dump($matches['wanted']);

Answer 6

Tripple checked, in multiple Versions.

<?php

    $string[] = "Foo's (match11) this (100:200 - 300:400) ";
    $string[] = "Foo has (not_matched) (100:200 - 300:400) ";
    $string[] = "Foo (100:200 - 300:400) ";

    $reg = "~(.*)(\([^\)]*\))?\s\(\d{3}\:\d{3}\s\-\s\d{3}\:\d{3}\)~iU";

    foreach ( $string as $s ){
        preg_match_all ( $reg, $s, $m , PREG_SET_ORDER);

        print "<br />String: ". $s . "<br /><pre>";
        print_r ( $m );
        print "</pre><br />OR";
    print "The String Required is: " . $m[0][1] . "<br />";
    }

?>

Its working, and you can get the needed string on

$output = $m[0][1];