正则表达式从Ruby中的单个字符串中提取几种模式的所有匹配项
[英]Regex to extract all matches of several patterns from a single string in Ruby
问题描述
After three hours I'm going to stop banging my head on the wall and ask for help. 
三个小时后，我将停止在墙上敲打头，寻求帮助。 This ought to be an easy regex, but I just can't quite get my mind around it today. 这应该是一个简单的正则表达式，但是今天我只是不太了解。
Given a short string and a few different patterns, I need to extract all the matching patterns from the string, where each pattern is a "whole word". 给定一个短字符串和一些不同的模式，我需要从字符串中提取所有匹配的模式，其中每个模式都是一个“整个单词”。
The patterns are: "YES", "NO", "MAYBE" , any sequence of asterisks ['*', '**', '***', '...'] , any number from 0 to 999, with the case of the text being case-insensitive. 模式是： "YES", "NO", "MAYBE" ，星号的任何序列['*', '**', '***', '...'] ，从0到999的任意数字，文字不区分大小写。
So if s = 'foo yes and no doo 5 boo **** bar far 13 not but no' the result would be ["yes", "no", "5", "****", "13", "no"] 因此，如果s = 'foo yes and no doo 5 boo **** bar far 13 not but no' ，结果将为["yes", "no", "5", "****", "13", "no"]
1 个解决方案
解决方案1
3 已采纳 2011-02-05 00:20:00
s = 'foo yes and no doo 5 boo * *** bar far 13 not but no YESTERDAY'
ms = s.scan(/(?:\b(?:yes|no|\d{1,3})\b|\*+)/i)
ms # => ["yes", "no", "5", "*", "***", "13", "no"]
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