将记录与来自两个不同表的通配符匹配

Question

I have two tables with the following data (amongst other data).

Table 1

Value 1
'003232339639
'00264644106272
0026461226291#

I need to match the second column in the table below using column 1 as an identifier

Table 2

Value 1      Value 2
00264        1
0026485      2
0026481      3
00322889     4
00323283     5
00323288     6

So the results I need will be as follows:

Result

Table 1, Value 1   Table 2, Value 2         
'003232339639......4
'00264644106272....1
0026461226291#.....1

Any help will be appreciated - very stuck here and doing it manually at the moment in excel.

I hope this format makes sense - first time I am using this forum.

Answer 1

Melany, the question is kind of confusing (not written correctly) perhaps that's why no one is responding. I'll make an attempt to explain how similar selects is done

SELECTING DATA FROM TABLE1 WHERE A MATCHING COLUMN (COL1) EXISTS IN BOTH TABLE

SELECT * FROM TABLE1
    INNER JOIN TABLE2
      ON TABLE1.COL1 = TABLE2.COL1
        AND TABLE1.COL1 = 'XYZ'

USING A SUBSELECT FOR THE SAME

    SELECT * FROM TABLE1
            WHERE COL1 IN(SELECT COL1 FROM TABLE2
                           WHERE COL1 = 'XYZ')

Answer 2

In SQL, the wildcard for one or more characters is % , and is to be used with the keyword LIKE .

So I suggest the following (if your purpose is really to match rows in Table1 for which Value1 begins like a value in Table2.Value1 ):

SELECT Table1.Value1, Table2.Value2 WHERE Table1.Value1 LIKE CONCAT(Table2.Value1, '%');

Edit: replace CONCAT(x, y) with x || y x || y for some DBMSs (SQLite for instance).