PYMongo：查询后，在每条记录中都返回_id，如何排除此记录？

Question

I am having problem when I do a query to mongodb using pymongo. I do not know how to avoid getting the _id for each record.

I am doing something like this,

result = db.meta.find(filters, [ 'model', 'fields.parent', 'fields.status', 'fields.slug', 'fields.firm', 'fields.properties'])

I do not want to iterate the cursor elements only to delete a field. Thanks,

Joaquin

Answer 1

您可以通过以下方式排除id对象：

db.meta.find({}, {"_id" : 0})

Answer 2

Does make any sense. The object id is core part of each document. Convert the BSON/JSON document to a native datastructure (depending on your implementation language) and remove _id on this level. Apart from that it does not make much sense what you are trying to accomplish.