同时接受套接字连接

Question

unsigned __int8 Decrypt(unsigned __int8 data[]);

for(;;)
    {
        if((sConnect=accept(sListen,(SOCKADDR*)&addr,&addrlen)) != INVALID_SOCKET)
        {
            Print("Socket Connected Successfully!");
            char buf[4095];
            recv(sListen,buf,sizeof(buf),0);
            Decrypt(buf); // Error:IntelliSense: argument of type "char *" is incompatible with parameter of type "unsigned char *"

        }

how can i fix this prob :-s

Answer 1

Why don't you use this signature:

unsigned char Decrypt(char *data);

instead of

unsigned __int8 Decrypt(unsigned __int8 data[]);

If you do so, you can easily pass buf to it, since even though buf is declared as char buf[4095] , it will become pointer type automatically when you pass it to Decrypt . No need to cast!

Answer 2

调用Decrypt时，将buf强制转换为无符号__int8。

Decrypt((unsigned __int8*)buf);

Answer 3

将其转换为正确的类型............................