在java中以给定速度以直线将对象从点（x1，y1）移动到点（x2，y2）的方法

Question

I have to write a method that moves an object (eg circle) in a straight line from one coordinate to another with a given speed. The object must get to the target point and stop. The speed correlates to the time in which it takes the object to reach the point (speed = 15 is equivalent to time = 15 ms for example). If someone could help me with the maths here, I would be garateful, please.

Answer 1

The interpolation formula for moving from point p0 to point p1 at constant speed is:

p(t) = p0*(1-t) + p1*t

where t is time that has been scaled to vary from 0 at the start to 1 at the end and p , p0 , and p1 are (x,y) coordinate pairs. Since Java doesn't have a built-in way to write the interpolation formula, you just apply it to the x and y components in parallel. The result is:

t = (time_now - start_time) / total_time;
x = x0*(1-t) + x1*t;
y = y0*(1-t) * y1*t;

This is the core calculation. To get the object to move, you follow these steps:

1. [Given: start_time, total_time, x0, y0, x1, y1]
2. put the circle at (x0, y0) and set time_now = start_time
3. until time_now == start_time + total_time, calculate (x, y) using the above, move the circle to (x, y), and increment time_now.

The time increment can be regular wall-clock time as determined by System.getTimeMillis() .