[英]Passing Argument to Python's Function
I have this function:我有这个功能:
def fun(arg1=1, arg2=2, arg3=3, arg4=4)
Now if I want to call fun with arg1=8 then I will do this:现在如果我想用 arg1=8 调用 fun 那么我会这样做:
fun(8)
and if I want to call it with arg1 = 8
and arg2 = 9
then I think this will do (correct me if I am wrong):如果我想用arg1 = 8
和arg2 = 9
调用它,那么我认为这可以做到(如果我错了,请纠正我):
fun(8,9) # LINE2
How to call fun
if I want to call it with the fourth argument = 10
, without passing other argument values (let another argument have default valued)?如果我想用第四个argument = 10
调用它而不传递其他参数值(让另一个参数具有默认值),如何调用fun
?
fun(arg4=10)
您只需要按名称引用特定参数。
只需提供您想要的参数,其他参数将获得它们的默认值:
fun(arg4=10)
>>> def fun(arg1=1,arg2=2,arg3=3,arg4=4):
print arg4
>>> fun(arg4='I called you!')
I called you!
Just call the specific argument you want.只需调用您想要的特定参数。
If you have:如果你有:
def fun(arg1=1,arg2=2,arg3=3,arg4=4):
print(arg1)
print(arg2)
print(arg3)
print(arg4)
and you call然后你打电话
fun(arg4=10)
you will get你会得到
1
2
3
10
and it should be what you want to get它应该是你想要的
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