[英]Umbraco 4.6+ - How to get all nodes by doctype in C#?
Using Umbraco 4.6+, is there a way to retrieve all nodes of a specific doctype in C#? 使用Umbraco 4.6+,有没有办法在C#中检索特定doctype的所有节点? I've been looking in the
umbraco.NodeFactory
namespace, but haven't found anything of use yet. 我一直在寻找
umbraco.NodeFactory
命名空间,但还没有发现任何有用的东西。
I was just doing this today, something like the below code should work (using umbraco.presentation.nodeFactory), call it with a nodeId of -1 to get the root node of the site and let it work it's way down: 我今天刚刚这样做,类似下面的代码应该工作(使用umbraco.presentation.nodeFactory),用nodeId为-1调用它来获取网站的根节点并让它工作下来:
private void DoSomethingWithAllNodesByType(int NodeId, string typeName)
{
var node = new Node(nodeId);
foreach (Node childNode in node.Children)
{
var child = childNode;
if (child.NodeTypeAlias == typeName)
{
//Do something
}
if (child.Children.Count > 0)
GetAllNodesByType(child, typeName);
}
}
Supposing you only eventually need a couple of nodes of the particular type, it would be more efficient to use the yield keyword to avoid retrieving more than you have to: 假设您最终只需要特定类型的几个节点,那么使用yield关键字以避免检索超过以下内容会更有效:
public static IEnumerable<INode> GetDescendants(this INode node)
{
foreach (INode child in node.ChildrenAsList)
{
yield return child;
foreach (INode grandChild in child.GetDescendants())
{
yield return grandChild;
}
}
yield break;
}
So your final call to get nodes by type will be: 因此,按类型获取节点的最终调用将是:
new Node(-1).GetDescendants().Where(x => x.NodeTypeAlias == "myNodeType")
So if you only want to get the first five, you can add .Take(5) to the end and you will only recurse through the first 5 results rather than pull out the whole tree. 因此,如果你只想获得前五个,你可以添加.Take(5)到最后,你只会通过前5个结果递归,而不是拉出整个树。
Or a recursive approach: 或者递归方法:
using umbraco.NodeFactory;
private static List<Node> FindChildren(Node currentNode, Func<Node, bool> predicate)
{
List<Node> result = new List<Node>();
var nodes = currentNode
.Children
.OfType<Node>()
.Where(predicate);
if (nodes.Count() != 0)
result.AddRange(nodes);
foreach (var child in currentNode.Children.OfType<Node>())
{
nodes = FindChildren(child, predicate);
if (nodes.Count() != 0)
result.AddRange(nodes);
}
return result;
}
void Example()
{
var nodes = FindChildren(new Node(-1), t => t.NodeTypeAlias.Equals("myDocType"));
// Do something...
}
If you're just creating a razor scripting file to be used by a macro (Umbraco 4.7+), I found this shorthand particularly useful... 如果您只是创建一个由宏(Umbraco 4.7+)使用的剃刀脚本文件,我发现这个简写特别有用......
var nodes = new Node(-1).Descendants("DocType").Where("Visible");
Hope this helps somebody! 希望这有助于某人!
In umbraco 7.0+ you can do it like this 在umbraco 7.0+中你可以这样做
foreach (var childNode in node.Children<ChildNodeType>())
{
...
}
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