HTML表单提交未显示javascript输出
[英]HTML Form submit not displaying the javascript output
问题描述
I wish to have a submit button (for the default form action), and an additional button for a second action. 
我希望有一个提交按钮（用于默认表单操作），以及一个用于第二个操作的附加按钮。
I have the following code: 我有以下代码：
<html>
<head><title></title>
<?PHP
$Input = "";
if(isset($_POST['Input'])) $Input = $_POST['Input'];
?>
</head>
<body>
<FORM id ="form1" method="post">
Input: <INPUT TYPE = "TEXT" VALUE ="<?php echo $Input;?>" NAME = "Input" SIZE="3">
<INPUT TYPE = "submit" id = "action1" VALUE = "action 1">
<INPUT TYPE = "button" id = "action2" VALUE = "action 2">
</FORM>
<br>
<script type="text/javascript">
var form = document.getElementById('form1');
form.onsubmit = function() {
document.getElementById("php_code_action1").innerHTML="<?php echo "action 1<br>"; ?>";
document.getElementById("php_code_action2").innerHTML="";
};
document.getElementById('action2').onclick = function()
{
document.getElementById("php_code_action2").innerHTML="<?php echo "action 2<br>"; ?>";
document.getElementById("php_code_action1").innerHTML="";
}
</script>
<span id="php_code_action1"> </span>
<span id="php_code_action2"> </span>
</body>
</html>
A click on the Action2 button works as I expect, but a click on "Action1" button has the page refresh and the output of action1 disappear. 单击Action2按钮的效果与我预期的一样，但是单击“ Action1”按钮将刷新页面，并且action1的输出消失。
Why is there a refresh, and how can I show the output of action1? 为什么要刷新，如何显示action1的输出？
2 个解决方案
解决方案1
4 已采纳 2011-02-20 14:54:37
form.onsubmit = function() {
document.getElementById("php_code_action1").innerHTML="<?php echo "action 1<br>"; ?>";
document.getElementById("php_code_action2").innerHTML="";
return false;
};
解决方案2
1 2011-02-20 14:53:47
You can write return false; 你可以写return false; in your onsubmit handler to prevent the usual action, ie form submission. 在您的onsubmit处理程序中，以防止执行常规操作，即表单提交。 Then the page shouldn't "refresh". 然后，该页面不应“刷新”。
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