[英]storage of data in memory
i want to know, how will the data be stored in memory ; 我想知道,如何将数据存储在内存中; or what will be the affect of the following code
或以下代码会产生什么影响
DATA1 DB 1,2,3 DATA1 DB 1,2,3
how does my data get stored.. if i am using a 80386 or above intel microprocessor.. i am a new with these stuff so kindly help! 我的数据如何存储..如果我使用的是80386或以上的英特尔微处理器..我是这些东西的新手,请帮忙!
Well, db
defines a sequence of bytes so you'll get the three bytes 1, 2 and 3 in increasing memory locations, starting at data1
. 好吧,
db
定义了一个字节序列,因此您将从data1
开始在递增的内存位置中获得三个字节1、2和3。
If data1
were at 0x00001234, the two statements db 1,2,3
and db 3,2,1
(that's one or the other, not one followed by the other) would give: 如果
data1
的值为0x00001234,则两个语句db 1,2,3
和db 3,2,1
(一个或另一个,而不是紧随其后的另一个)将给出:
DB 1,2,3 DB 3,2,1
+------+ +------+
0x00001234 | 0x01 | | 0x03 |
+------+ +------+
0x00001235 | 0x02 | | 0x02 |
+------+ +------+
0x00001236 | 0x03 | | 0x01 |
+------+ +------+
For example, check out this debug
session: 例如,签出以下
debug
会话:
c:\src> debug
-a 100
1388:0100 db 1,2,3,4
1388:0104 db 9,8,7,6
1388:0108
-d 100 10f
1388:0100 01 02 03 04 09 08 07 06-00 00 00 00 00 00 00 00 ................
-q
c:\src> _
You can see that the 1
, 2
, 3
and 4
(in that order) go into memory locations 0x0100
through 0x0103
and the 9
, 8
, 7
and 6
(again, in the specified order) go into memory locations 0x0104
through 0x0107
. 可以看到的是,
1
, 2
, 3
和4
(按该顺序)进入存储器位置0x0100
通过0x0103
和9
, 8
, 7
和6
(再次,按照指定的顺序)进入存储器位置0x0104
通过0x0107
。
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