[英]Find the words start from a special character java
I want to find the words that start with a "#" sign in a string in java. 我想在java中的字符串中找到以“#”符号开头的单词。 There can be spaces between the sign and the word as well.
标志和单词之间也可以有空格。
The string "hi #how are # you"
shall give the output as : 字符串
"hi #how are # you"
将输出为:
how
you
I have tried this with regex, but still could not find a suitable pattern. 我用regex尝试了这个,但仍然找不到合适的模式。 Please help me on this.
请帮帮我。
Thanks. 谢谢。
Use #\\s*(\\w+)
as your regex. 使用
#\\s*(\\w+)
作为正则表达式。
String yourString = "hi #how are # you";
Matcher matcher = Pattern.compile("#\\s*(\\w+)").matcher(yourString);
while (matcher.find()) {
System.out.println(matcher.group(1));
}
This will print out: 这将打印出来:
how
you
Try this expression: 试试这个表达式:
# *(\w+)
This says, match # then match 0 or more spaces and 1 or more letters 这样说,匹配#然后匹配0或更多空格和1个或多个字母
I think you may be best off using the split method on your string (mystring.split(' ')) and treating the two cases separately. 我认为你可能最好在字符串上使用split方法(mystring.split(''))并分别处理这两种情况。 Regex can be hard to maintain and read if you're going to have multiple people updating the code.
如果您要让多个人更新代码,正则表达式很难维护和阅读。
if (word.charAt(0) == '#') {
if (word.length() == 1) {
// use next word
} else {
// just use current word without the #
}
}
Here's a non-regular expression approach... 这是一种非正则表达方式......
Replace all occurrences of a # followed by a space in your string with a # 用#替换字符串中所有出现的#后跟一个空格
myString.replaceAll("\\s#", "#") myString.replaceAll(“\\ s#”,“#”)
NOw split the string into tokens using the space as your delimited character 否则使用空格作为分隔字符将字符串拆分为标记
String[] words = myString.split(" ") String [] words = myString.split(“”)
Finally iterate over your words and check for the leading character 最后迭代你的单词并检查主角
word.startsWith("#") word.startsWith( “#”)
String mSentence = "The quick brown fox jumped over the lazy dog.";
int juIndex = mSentence.indexOf("ju");
System.out.println("position of jumped= "+juIndex);
System.out.println(mSentence.substring(juIndex, juIndex+15));
output : jumped over the
its working code...enjoy:)
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