[英]How to find a middle value or node from linked list in java?
I have the 50 values in linked list.how to find a middle value or node of linked list? 我在链表中有50个值。如何找到链表的中间值或节点?
List list = new LinkedList();
for (int i = 0; i < 50; i++) {
list.add(String.valueOf(i));
}
int size = list.size();
int middle = (size / 2);
System.out.println(list.get(middle).toString());...
i got an answer like this.... But my team leader said to find in another way? 我得到了这样的答案。...但是我的团队负责人说要找到另一种方法? Is there any other built in method to iterate in linked list?i tried ...but i dint get any built in method for finding middle value...And or can u any one suggest another logic to find the value of middle node in linke list?
我是否尝试过其他任何内置方法来迭代链接列表?但我尝试得到任何用于找到中间值的内置方法...或者您是否可以建议另一种逻辑来查找中间节点的值?链接列表?
thank you....... 谢谢.......
Get 2 references to the same list. 获得2个引用到同一列表。
In a single loop:
Advance the 1st list 2 nodes at a time.
Advance the 2nd list 1 node at a time.
Loop until the 1st loop reaches the end.
List list = new LinkedList();
for (int i = 0; i < 50; i++) {
list.add(String.valueOf(i));
}
int end = list.size() - 1;
int start = 0;
while (start > end) {
start++;
end--;
}
if(start == end) //The arrays length is an odd number and you found the middle
return start;
else //The arrays length is an even number and there really isn't a middle
//Do something else here because you have an even number
也许您的团队负责人建议您使用ArrayList而不是LinkedList。
List<String> list = new ArrayList<String>(50);
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