Java：如何将二进制值的字符串转换为Float，反之亦然？

Question

如何将12345.12346f的浮点值转换为二进制值的字符串，即“0011010101010101”，反之亦然？

Answer 1

I'm not sure it is what you want, but here's a solution to have the binary representation of the IEEE 754 floating-point "double format" bit layout for a float (it is basically the memory representation of a float) :

int intBits = Float.floatToIntBits(yourFloat); 
String binary = Integer.toBinaryString(intBits);

For the reverse procedure :

int intBits = Integer.parseInt(myString, 2);
float myFloat = Float.intBitsToFloat(intBits);

Answer 2

For signed Floats, use Long or BigInteger to parse the string. Casting by int causes the digit at first of 32 bits be intepreted as sign digit. procedure :

int intBits = Float.floatToIntBits(yourFloat); 
String binary = Integer.toBinaryString(intBits);

reverse procedure :

int intBits = new BigInteger(myString, 2).intValue();
// int intBits = (int) Long.parseLong(myString, 2);
float myFloat = Float.intBitsToFloat(intBits);

Answer 3

Working sample:

class F { 
  public static void main( String ... args ) { 
    System.out.println(
          Integer.toBinaryString( 
             Float.floatToIntBits(12345.12346f)
          ) 
     );
  }
}

Output:

1000110010000001110010001111110

Answer 4

You can get the bit representation of a Java Float value using

Float.floatToIntBits(float f);

Once you have done that you can test each bit of the resulting int in turn, starting with the highest, and find out if it set, writing a '1' if it is set and a '0' if not.