选择最大不同值

Question

I have a database table with a phone number (string) and a name (string)

There same number may have different names in different rows

given a certain number I want to select the most frequently used name

For instance given the following data if using 555.1234 I should get back from the query Frank

Number   |  Name
-----------------
555.1234 |  Frank
555.1234 |  Fran
555.1234 |  James
555.1234 |  Frank
555.1233 |  Jesse

It seems like I should be able to combine distinct and Max somehow, but I can't come up with the right query to do this. Any ideas?

Answer 1

If you don't know what the phone number will be to pass into the query, then you can use the following:

SELECT Number, Name, COUNT(Name) AS NameCount
FROM test
GROUP BY Number, Name
HAVING NameCount > 1
Order BY NameCount DESC
LIMIT 1

That will give you the most frequently used phone number by a single name, and return the phone, name and the count.

Here is the test table that I used to try out the query, and the values thereof:

Number   | Name
555.1234 | Frank
555.1234 | Fran
555.1234 | James
555.1234 | Frank
555.1234 | Jesse
555.2234 | Frank
555.1234 | Jesse
555.1234 | Frank

Let me know if that works for you!

Answer 2

If, as I understand the question, you have a specific number as input, then this may work depending on the database you are using. Capsule's comment made me realize that might not be the situation. Edit Changed to Count(*) for (I think) better clarity based on Jack's good comment.

select Top 1 Name, Count(*) total 
   from phone where number = '555.1234' 
   group by name 
   order by total desc