使用 Python IMAP 获取发件人电子邮件地址

Question

I have this python IMAP script, but my problem is that, every time I want to get the sender's email address, (From), I always get the sender's first name followed by their email address:

Example:

Souleiman Benhida <souleb@gmail.com>

How can i just extract the email address ( souleb@gmail.com )

I did this before, in PHP:

    $headerinfo = imap_headerinfo($connection, $count)
    or die("Couldn't get header for message " . $count . " : " . imap_last_error());
$from = $headerinfo->fromaddress;

But, in python I can only get the full name w/address, how can I get the address alone? I currently use this:

    typ, data = M.fetch(num, '(RFC822)')
mail = email.message_from_string(data[0][1])
headers = HeaderParser().parsestr(data[0][1]) 
message = parse_message(mail)  #body
org = headers['From']

Thanks!

Answer 1

Just one more step, using email.utils :

email.utils.parseaddr(address)

Parse address – which should be the value of some address-containing field such as To or Cc – into its constituent realname and email address parts. Returns a tuple of that information, unless the parse fails, in which case a 2-tuple of ('', '') is returned.

Note: originally referenced rfc822 , which is now deprecated.

Answer 2

to = email.utils.parseaddr(msg['cc'])

这对我有用。

Answer 3

My external lib https://github.com/ikvk/imap_tools let you work with mail instead read IMAP specifications.

from imap_tools import MailBox, A

# get all emails from INBOX folder
with MailBox('imap.mail.com').login('test@mail.com', 'pwd', 'INBOX') as mailbox:
    for msg in mailbox.fetch(A(all=True)):
        print(msg.date, msg.from_, msg.to, len(msg.text or msg.html))

msg.from_, msg.to - parsed addresses, like: 'Sender@ya.ru'