如何确定用户输入中的最大值和最小值？

Question

I'm trying to get the highest and lowest numbers entered by the user. The code below seems to be mostly working but I can't seem to get the right number for the lowest value. What am I doing wrong?

import java.io.*;

public class jem3
{
    public static void main(String []args)
    {
        BufferedReader dataIn = new BufferedReader(new InputStreamReader( System.in ));        
        int high=0;
        int lowest=1;
        int num=0;
        int A=0;

        System.out.println("Enter number");

        for(int a=0;a<10;a++)
        {
            try
            {
                num=Integer.parseInt(dataIn.readLine());
            }
            catch(IOException e)
            {
                System.out.println("error");
            }

            if(num>high)
            {
                high=num;
            }

            if(num>=A)
            {
                A=lowest;
            }                        
        }

        System.out.println("highest is:"+  high);
        System.out.println("lowest is: "+A);
    }
}

Answer 1

What is the purpose of A ? You're not modifying lowest either. You're close, try this:

num = ...
if ( num > max ) max = num;
if ( num < min ) min = num;

System.out.println("Highest: " + max);
System.out.println("Lowest: " + min);

Answer 2

import java.io.*;

public class jem3{

  public static void main(String []args){
  BufferedReader dataIn = new BufferedReader(new InputStreamReader(System.in));        
    int high=0;
    int lowest=0;
    int num=0;
    boolean test = true;

    System.out.println("Enter number");

    for(int a=0;a<10;a++)
    {
        try
        {
            num=Integer.parseInt(dataIn.readLine());
        }
        catch(IOException e)
        {
            System.out.println("error");
        }

        if(num>high)
        {
            high=num;
        }
        //add an initial value to 'lowest'
        if (test)
            lowest = num;
            test = false;

        if(num < lowest)
        {
            lowest = num;
        }                        
    }

    System.out.println("highest is:"+  high);
    System.out.println("lowest is: "+ lowest);
    }
}

Answer 3

import java.io.*;   
public class jem3
{
    public static void main(String []args)
    {
    BufferedReader dataIn = new BufferedReader(new InputStreamReader( System.in ));     
    int high;
    int lowest;
    int num;
    System.out.println("Enter number");

    num=Integer.parseInt(dataIn.readLine());
    lowest = highest = num;

    for(int a=0;a<10;a++)
    {
        try

            {

                num=Integer.parseInt(dataIn.readLine());
            }
            catch(IOException e)
            {
                System.out.println("error");
            }


            if(num>high)
            {
                high=num;
            }
            if(num<lowest)
            {
                lowest=num;
            }

    }
    System.out.println("highest is:"+  high);
    System.out.println("lowest is: "+lowest);


    }
}

i added code after reeading first line to set high and lowest, so if user will give you 10 numbers '9' it will output lowest number being '9' and not 1 as it would (similiar with high).

Answer 4

you are on the right track for capturing highest . you need to apply similar logic for lowest .