PHP正则表达式为黎巴嫩电话号码

Question

i am writing a php app that asks people for their phone number in lebanon. I don't want to be very strict in the entry format so i'm running into some trouble validating.

A lebanese phone number looks like that.

961 3 123456

961 : the country code. i want it to be valid with or without it.

3 : the area code. here's where it is tricky. the possible area codes are 03, 70 and 71. when the country code is present, 03 drops the 0 and becomes 3 while 70 and 71 are as is with or without country code.

123456 : the phone number, always 6 digits.

here are the formats i'm trying to validate:

961 3 123456
961 70 123456
961 71 123456
03 123456
70 123456
71 123456

the spaces are here just for the sake of clarity, i am validating after stripping all spaces and non alphanumeric characters.

that's it, would be great if someone can help. thanks

Answer 1

I'm sure there's a slicker way to do it, but

^(961(3|70|71)|(03|70|71))\d{6}$

seems to work, assuming I understand the requirements.

Answer 2

^((961)?(7(0|1))|(961|0)3)[0-9]{6}$

It's a composition of these three regexes:

(961)?(7(0|1))  // 70 and 71 prefixes
(961|0)3        // (0)3 prefix
[0-9]{6}        // main number

Answer 3

Allowing for spaces or common separator chars (though I know you said you weren't concerned about them):

^((961[\s+-]*(3|7(0|1)))|(03|7(0|1)))[\s+-]*\d{6}$

http://regexr.com?2t89v

Answer 4

This regex handle all the area codes in lebanon https://en.wikipedia.org/wiki/Telephone_numbers_in_Lebanon

^(?:\+961|961)?(1|0?3[0-9]?|[4-6]|70|71|76|78|79|7|81?|9)\d{6}$

You can check on regexr