在 Node.js 中，我如何知道 `this` 模块的路径？

Question

In a Node.js module I would like to open a file--ie, with fs.readFile() --that is contained in the same directory as my module. By which I mean it is in the same directory as the ./node_modules/<module_name>/index.js file.

It looks like all relative path operations which are performed by the fs module take place relative to the directory in which Node.js is started. As such, I think I need to know how to get the path of the current Node.js module which is executing.

Thanks.

Answer 1

As david van brink mentioned in the comments, the correct solution is to use __dirname . This global variable will return the path of the currently executing script (ie you might need to use ../ to reach the root of your module).

For example:

var path = require("path");
require(path.join(__dirname, '/models'));

Just to save someone from a headache.