如何从URL获取Domain.ext？ PHP的

Question

if we have

 $url = "http://subdomain.domin.ext/somepath/file.php";

how to get the domain.ext

when I used

 $parse = parse_url($url);
 $domin = $parse[host];

then echo "$domain"; //this returns subdomain.domin.ext echo "$domain"; //this returns subdomain.domin.ext

is there any idea to get domain.ext?

Answer 1

$url = "http://subdomain.domin.ext/somepath/file.php";
$parse = parse_url($url);
$domain = $parse['host'];
$lastDot = strrpos($domain,'.');
$ext = substr($domain,$lastDot+1);

This will get you "ext" (eg "com" or "gov"). In the case of something like amazon.co.uk, it will give you "uk". If you need "co.uk", you will need to add logic to detect certain TLDs (eg "uk") and go to the second dot on those cases.

Answer 2

If you have a specific domain with different TLDs, like mysite with .co.uk and .com , than you can basically do the following:

$url = 'http://mysite.co.uk/some-dir/';
$domain_pos = strpos($url, 'mysite');
$domain = substr($url, $domain_pos);
$ext_pos = strpos($domain, '/');
if($ext_pos !== false) { // extra check for paths/sub-dirs
  $domain = substr($domain, 0, $ext_pos); 
}
echo $domain;

Returns mysite.co.uk or whatever TLD that gets assigned to the $url .

Note the extra check for paths and sub directories. :)

Answer 3

<?php
$url = "http://subdomain.domain.ext/somepath/file.php";
$parse = parse_url($url);
$domain = substr(strrchr($parse['host'], '.'), 1);
$domain = substr(strrchr(substr($parse['host'], 0, -strlen($domain)), '.'), 1). '.'. $domain;
if(in_array(strstr($domain, '.', true), array('co', 'com', 'net', 'org', 'edu', 'gov', 'mil')))
{
  $domain = substr(strrchr(substr($parse['host'], 0, -strlen($domain)), '.'), 1). '.'. $domain;
}
?>