简体   繁体   English

如何编写删除所有“大孩子”元素的Hibernate HQL查询?

[英]How to write Hibernate HQL query which remove all “grand children” elements?

I have schools, which contains groups, which contains students. 我有学校,其中包含团体,其中包含学生。

I would like to remove all students from specific school. 我想将所有学生从特定学校中删除。

In SQL I can write the following query: 在SQL中,我可以编写以下查询:

DELETE FROM students1 
WHERE students1.group_id IN 
      (SELECT id FROM group1 WHERE group1.school_id = :school_id)

How to transform this SQL query to Hibernate HQL? 如何将此SQL查询转换为Hibernate HQL?

I use H2 database engine. 我使用H2数据库引擎。

(My real query is more complex and simple cascade deletion of school is not suitable for me). (我真正的查询更复杂,简单的级联删除学校不适合我)。

The working script follows: 工作脚本如下:

DELETE FROM Student AS s
WHERE s IN
    (SELECT s FROM Student AS s WHERE s.group IN
        (SELECT g FROM Group AS g WHERE g.school IN
            (SELECT s FROM School s WHERE s.id = :schoolId)))

Thanks to comments of doc_180 感谢doc_180的评论

You can't use JOIN (either explicit or implicit) in Hibernate's bulk queries (like deletes) currently, but you can use them in subqueries, something like this: 当前,您不能在Hibernate的批量查询(如删除)中使用JOIN (显式或隐式),但可以在子查询中使用它们,如下所示:

DELETE FROM Student st
WHERE st IN (
    SELECT st 
    FROM School s JOIN s.groups g JOIN g.students st
    WHERE s = :s
)

Try this: 尝试这个:

 String hql="delete from Student where group.school=:school";
 session.createQuery(hql).setParameter("school", schoolObject).executeUpdate();

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM