[英]How to show #s in vertical from Horizontal through simple regex?
I have the following numbers as shown below: 我有以下数字,如下所示:
1234567890
I would like to get the result as: 我想得到的结果如下:
1
2
3
4
5
6
7
8
9
0
(Horizontal to Vertical). (水平到垂直)。 Please help me to achieve it via simple regex or through editplus.
请帮我通过简单的正则表达式或通过editplus实现它。
Thanks in advance !!! 提前致谢 !!!
You don't need a regular expression for this; 你不需要正则表达式; all you're trying to accomplish is to insert a newline character between each element in your string.
你要做的就是在字符串中的每个元素之间插入一个换行符。
If you're using C#, you can use the following: 如果您使用的是C#,则可以使用以下内容:
string s = "1234567890";
string.Join(Environment.NewLine, s.ToCharArray());
Note that if your number is of a numeric data type (eg, int
), you'll likely need to convert it to a string. 请注意,如果您的数字是数字数据类型(例如,
int
),您可能需要将其转换为字符串。 In C#, this is as simple as calling the .ToString()
method, for example: 在C#中,这就像调用
.ToString()
方法一样简单,例如:
int x = 1234567890;
string s = x.ToString();
sorry I don't have editplus, but this should work (tested in notepad++) 对不起,我没有editplus,但这应该工作(在记事本++中测试)
Find: 找:
([0-9])
replace: 更换:
\1\r\n
make sure to have regular expression search on (this may only pertain to notepad++) 确保有正则表达式搜索(这可能只适用于记事本++)
the () creates a regular expression group, that may then be back referenced via the "\\1" (see the link for a primer) the "\\r\\n" are just CRLF ()创建一个正则表达式组,然后可以通过“\\ 1” 反向引用 (参见引言的链接)“\\ r \\ n”只是CRLF
Replace .
替换
.
with &\\n
in editplus. 使用
&\\n
plus在editplus中。
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