如何通过python ctypes将二进制缓冲区传递给ac函数

Question

I'd like to wrap the following c function bar() in python 2.x and invoke it via the ctypes module, both on Linux and Windows:

#include <stdio.h>

#ifdef FOO_DLL
#define FOO_API __declspec(dllexport)
#else
#define FOO_API extern
#endif

FOO_API unsigned int bar(const void* data, unsigned int len) 
{
   printf("%p (%d bytes)\n", data, len);
   return len;
}

To compile the shared library I use scons:

import sys

env = Environment()
if sys.platform == 'win32':
  env.Append(CFLAGS=['-DFOO_DLL'])

env.SharedLibrary('foo', ['foo.c'])

Finally I load the respective shared lib and invoke the function:

import sys
import struct
from ctypes import *

if sys.platform == 'win32':
  libfoo = windll.LoadLibrary('foo')
else:
  libfoo = cdll.LoadLibrary('./libfoo.so')

data = struct.pack('BBB', 0, 1, 2)
libfoo.bar(data, len(data))

To my surprise this seems to work flawlessly under Linux, but on Windows the code throws an error that makes me suspects that this isn't the proper way to do things:

$ python foo.py
00B520C4 (3 bytes)
Traceback (most recent call last):
  File "foo.py", line 11, in <module>
    libfoo.bar(data, len(data))
ValueError: Procedure probably called with too many arguments (8 bytes in excess)

What would be the right approach?

On Linux (Ubuntu 10.10 64bit) I'm using Python 2.6.6, gcc 4.4.5 and on Windows (XP 32bit, in a VirtualBox) Python 2.7.1 and VS2010 Express.

Answer 1

Both Windows and Linux should use cdll which results in the C calling convention. The Python code at present calls your Windows DLL using stdcall but it's really a cdecl function. The difference between cdll and windll is just the calling convention used.

That error message is a textbook calling convention mismatch error, for what it's worth.