将int数组转换为C中的指针

Question

void test()
{
       int buf[1000];

       //populate buf
       foo(buf);//is this correct? Can we pass buf as a pointer that foo expects?



}
void foo(void*ptr)
{}

EDIT: if foo were fwrite, would the above(mechanism of passing buf so as to supply fwrite with content to write into some file) still be applicable?

Answer 1

Its perfectly valid in C. foo argument is a pointer that can point to any type . When you pass an array, it decays to a pointer pointing to the first element of the array (ie,address location of the first element is passed). So,

 ptr -> &buf[0] ;

Answer 2

Yes you can do that.

buf is the base pointer of the array.

Answer 3

是的，您将始终将buf用作指针。

Answer 4

Yes its correct. You can use the "ptr" pointer in your foo function. http://codepad.org/HwYd0GAh

Answer 5

As the other answers pointed out, yes , you can pass buf to the function.

However, inside the function, the variable ptr has type void* . And there's only a few things you can do with ptr itself. Usually you convert it (with or without a cast) to something relevant, like int* .

void foo(void *ptr) {
    int *iptr;
    iptr = ptr;
    /* now use iptr */
}