MySQL：在不知道该列值的情况下选择1列相同的行？

Question

With the following integer columns:
iid, pid, aid

I would end up with something like:

1,1,1
1,1,2
1,1,3
2,1,1
2,1,2
2,1,4

If I want to select iid where pid is 1 and aid is 1,2,3, what's the best way to get that? Doing a

SELECT iid WHERE pid=1 and (aid=1 OR aid=2 OR aid=3)

returns every row but the last one.

Is there a better table structure to use? pid is a row in another table that can have several values. This table gives me the iid, a master id for that row with certain values. There is no set number of values, though, so it seems like I need a 1 to many table, but trying to get that down to the 1 iid seems inefficient.

Answer 1

If you want to use your current table structure, you could do the following to select the iid you want.

SELECT 
     iid, pid, GROUP_CONCAT(aid) as grp 
FROM 
     test 
WHERE 
     pid = 1 
GROUP BY 
     pid, iid 
HAVING 
     grp = '1,2,3';

+------+------+-------+
| iid  | pid  | grp   |
+------+------+-------+
|    1 |    1 | 1,2,3 |
+------+------+-------+
1 row in set (0.06 sec)

With the group query you can see the AID attributes together grouped by PID and then IID.

SELECT iid, pid, GROUP_CONCAT(aid) as grp 
FROM test 
GROUP BY pid, iid;
+------+------+-------+
| iid  | pid  | grp   |
+------+------+-------+
|    1 |    1 | 1,2,3 |
|    2 |    1 | 1,2,4 |
+------+------+-------+
2 rows in set (0.03 sec)